Take a 19 in. and 0 = 45°. (Figure 1) Figure a 8 in. 2 in. 2 in. 8 in.-- 2 in. 1 of 1 Part C Determine the product of inertia Iuv for the beam's cross-sectional area. Express your answer using three significant figures. Iuv = Submit OF 15. ΑΣΦ 11 vec Provide Feedback Previous Answers Request Answer X Incorrect; Try Again; 7 attempts remaining ? in 4
Take a 19 in. and 0 = 45°. (Figure 1) Figure a 8 in. 2 in. 2 in. 8 in.-- 2 in. 1 of 1 Part C Determine the product of inertia Iuv for the beam's cross-sectional area. Express your answer using three significant figures. Iuv = Submit OF 15. ΑΣΦ 11 vec Provide Feedback Previous Answers Request Answer X Incorrect; Try Again; 7 attempts remaining ? in 4
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question
it seems like Iuv should be zero because xbar is zero distance away from the x-axis
![Take a = 19 in. and 0 = 45° . (Figure 1)
Figure
8 in.
2 in. 2 in.
8 in.-
11
2 in.
1 of 1
X
Part C
Determine the product of inertia Iv for the beam's cross-sectional area.
Express your answer using three significant figures.
15. ΑΣΦ ↓↑ vec
Iuv
=
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 7 attempts remaining
Provide Feedback
?
in 4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F919fc4f8-bc37-4123-8b2a-9ca8cd02385f%2F81ab3dce-bb4d-4d86-9213-47269cf0dfd4%2Ft2uqcb9_processed.png&w=3840&q=75)
Transcribed Image Text:Take a = 19 in. and 0 = 45° . (Figure 1)
Figure
8 in.
2 in. 2 in.
8 in.-
11
2 in.
1 of 1
X
Part C
Determine the product of inertia Iv for the beam's cross-sectional area.
Express your answer using three significant figures.
15. ΑΣΦ ↓↑ vec
Iuv
=
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 7 attempts remaining
Provide Feedback
?
in 4
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