A Proton between Oppositely Charged PlatesA uniform electric field exists in the region between twooppositely charged parallel plates 1.68 cm apart. A proton isreleased from rest at the surface of the positively chargedplate and strikes the surface of the opposite plate in a timeinterval 1.48x10-6s Part AFind the magnitude of the electric field.Use 1.60x10-19 C for the magnitude of the charge on an electron and 1.67x10 4 kg for the mass of a proton.> View Available Hint(s)ΑΣφN/CSubmitPart BFind the speed of the proton at the moment it strikes the negatively charged plate.View Available Hint(s)m/s

Given data: Distance between the plates, d=1.68 cm = 0.0168 m Time interval, t=1.48×10-6 s Mass of…

A uniform electric field exists in the region between two oppositely charged parallel plates 1.68 cm apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval 1.48x10 6s

A uniform electric field exists in the region between two oppositely charged parallel plates 1.68 cm apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval 1.48x10 6s

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

The plates of a parallel plate capacitor are 3.28mm apart, and have an area of 12.2cm². Each plate carries a charge of magnitude 4.35x10–³ C. The plates are in vacuum. What is the magnitude of electric field between the plates?
A parallel plate capacitor is formed of two 10 cm × 10 cm plates spaced 1 cm apart. The plates are charged to ±1 nC. An electron is shot through a very small hole in the positive plate. What is the slowest speed the electron can have if it is to reach the nega- tive plate? +1 nC -1 nC 1 cm ++++
Each plate of a parallel-plate capacitor is circular and has diameter 24.0 cm. The plates are 15.0 μm apart, and carry charges of +8.00 μC and -8.00 μC. An electron begins at rest at the negative plate and is released. What is its speed when it reaches the other plate? 1.45 x 107 m/s 5.13 x 106 m/s 2.05 x 107 m/s 1.024 x 107 m/s 7.26 x 106 m/s
An electron is placed in a uniform electric field of 32nN/C directed north created by two horizontal parallel plates that are 131fm apart. The electron accelerates from rest, starting at the negative plate. What is the net force and acceleration acting on the electron? How long did it take the electron to get from one side of the plate to the other?
Oppositely charged parallel plates are separated by 6.30 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? N/C (b) What is the magnitude of the force on an electron between the plates? N (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.80 mm from the positive plate?
From a distance of 10 cm, a proton is projected with a speed of v = 4.0 × 106 m/s directly at a large, positively charged plate whose charge density is o = 3.5 x 10-5 C/m². (See below.) -10 cm- 4.0 X 106 m/s (a) Does the proton reach the plate? O Yes No ++ ++ ++ ++ ++ ++ ++ ++ (b) If not, how far from the plate (in cm) does it turn around? (If the proton does reach the plate, enter zero.) X cm
Oppositely charged parallel plates are separated by 5.10 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? N/C (b) What is the magnitude of the force on an electron between the plates? N (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.92 mm from the positive plate?
A uniform electric field exists in the region between two oppositely charged plane parallel plates. An electron is released from rest at the surface of the negatively charged plate and strikes the surface of the opposite plate, 3.40 cm distant from the first, in a time interval of 1.90×10-8 s Part A Part B Find the magnitude of this electric field. Find the speed of the electron when it strikes the second plate. Express your answer in newtons per coulomb. Express your answer in meters per second. να ΑΣφ 5 ? | να ΑΣφ ? E = N/C m/s
An electron and a proton are each placed at rest in a uniform electric field of magnitude 518 N/C. Calculate the speed of each particle 47.6 ns after being released.
The positive and negative plates of a parallel-plate capacitor have an area of 1.60 cm by 1.60 cm. Their surface charge densities are +1.00×10-6 C/m2and -1.00×10-6 C/m2, respectively. A proton moving parallel to the plates enters the middle of the space between them at a speed of 2.65×106 m/s. Assuming the field outside the capacitor is 0 and the field inside is uniform, how far to the side will the proton's path have deviated when it gets to the far end of the capacitor?
In the figure, an electron is shot from an infinite distance along the y axis and through the origin. Three other charged particles are fixed in place on the axes. The electron has an initial speed of vo = 15.0 m/s. What is its speed (m/s) when it passes through the origin? 91 = +6e (left and right sides) 92 = -5e d = 2.00 m 7 d 72 71
If you have two fixed particles with electric charges q1= 5 μC and q2= 17μC separated by a distance of 50 cm, determine the place where you have to place a third particle with electric charge q3=2µC in such a way that it remains at rest when released. q1 q2