A line of charge is placed along the negative x axis from x=-0.4m to x=0. The charge is uniformly distributed with linear charge density 5.16pC/m. A proton is released from rest at a point on the positive x axis 1.54m. When the proton has a speed of 479.2m/s, how far will it have moved (in m}?
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- Figure 1 shows two sets of equi-potential surfaces due to charge q₁ and charge 92. An external agent moves an electron (e = 1.6 × 10-¹⁹ C) from position a to position b. 50 V91 25 V 110 V 110 V 92 50 V Figure 1: Two sets of equi-potential surfaces a) State whether the charges q₁ and q2 are positive or negative. Justify your answer.Oppositely charged parallel plates are separated by 5.64 mm. A potential difference of 600 v exists between the plates. (a) What is the magnitude of the electric field between the plates? N/C (b) What is the magnitude of the force on an electron between the plates? (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.92 mm from the positive plate?Consider a parallel-plate capacitor with plate separation d, plate area A, whose plates have charge ±Q. A particle of charge q < 0 and mass m is released from rest at the negative plate of the capacitor and allowed to accelerate towards the positive plate. With what speed does the charge strike the positive plate? Answer in terms of d, A, Q, q, m, and/or e0.
- Oppositely charged parallel plates are separated by 4.49 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? N/C (b) What is the magnitude of the force on an electron between the plates? (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.72 mm from the positive plate?Two charged, parallel, flat conducting surfaces are spaced d = 1.1 cm apart and produce a potential difference ΔV = 715 V between them. An electron is projected from one surface directly toward the second. What is the initial speed of the electron if its comes to rest just at the second surface?Two red blood cells each have a mass of 5.05 × 10-¹4 kg and carry a negative charge spread uniformly over their surfaces. The repulsion arising from the excess charge prevents the cells from clumping together. Once cell carries -2.60 pC of charge and the other -2.70 pC, and each cell can be modeled as a sphere 8.20 µm in diameter. What minimum relative speed u would the red blood cells need when very far away from each other to get close enough to just touch? Ignore viscous drag from the surrounding liquid. V = What is the magnitude of the maximum acceleration amax of each cell? Cmax = m/s m/s²
- Oppositely charged parallel plates are separated by 5.36 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field strength between the plates? N/C(b) What is the magnitude of the force on an electron between the plates? N(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.92 mm from the positive plate? JOppositely charged parallel plates are separated by 3.77 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? N/C(b) What is the magnitude of the force on an electron between the plates? N(c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.66 mm from the positive plate? JThe figure below shows a proton entering a parallel-plate capacitor with a speed of 1.80×105 m/s. The proton travels a horizontal distance x = 5.90 cm through the essentially uniform electric field. The electric field of the capacitor has deflected the proton downward by a distance of d = 0.820 cm at the point where the proton exits the capacitor. (You can neglect the effects of gravity.) + + + + + + + + + Using kinematics, find the vertical acceleration (including sign) of the proton in this electric field. Submit Answer Tries 0/32 Find the magnitude of the force on the proton. Submit Answer Tries 0/100 Find the strength of the electric field within the capacitor. Submit Answer Tries 0/32 Find the speed of the proton when it exits the capacitor. Submit Answer Tries 0/32
- The drawing shows an electron entering the lower left side of a parallel plate capacitor and exiting at the upper right side. The initial speed of the electron is 3.13 × 106 m/s. The capacitor is 2.00 cm long, and its plates are separated by 0.150 cm. Assume that the electric field between the plates is uniform everywhere and find its magnitude. 15.30 + A + 2.00 cm Number i + + + 0.150 cm UnitsThe ink drops have a mass mmm = 1.00×10−11 kg each and leave the nozzle and travel horizontally toward the paper at velocity v = 15.0 m/s. The drops pass through a charging unit that gives each drop a positive charge q by causing it to lose some electrons. The drops then pass between parallel deflecting plates of length D0D0D_0 = 2.15 cm, where there is a uniform vertical electric field with magnitude E = 7.70×104 N/C. 1) If a drop is to be deflected a distance d = 0.340 mmmm by the time it reaches the end of the deflection plate, what magnitude of charge q must be given to the drop? Assume that the density of the ink drop is 1000 kg/m3 , and ignore the effects of gravity.