A Ti-6AI-25n-4Zr-6Mo titanium alloy subjected to a stress of 20 ksi. How long can the alloy be used under this stress at 932 deg. F so that no more than 0.2% creep strain will occur. 1000p TH-6AL-2Sn-4Z-6Mo TH-6AI-2S-Z6Mo-Si IMI 829 -IMI 834 Alpha 2 (TBAI) General Gamma (TIAI) General ---- INCONEL 718 O IMI 829 ROC A T-25A-1ONb-3V-IMo TI3AI ROC 100 10 28 30 32 34 36 38 40 Larsen-Miller parameter, P = (460'F + T°F)(20 + log 1 (h)] × 10 Stress (ksi)
A Ti-6AI-25n-4Zr-6Mo titanium alloy subjected to a stress of 20 ksi. How long can the alloy be used under this stress at 932 deg. F so that no more than 0.2% creep strain will occur. 1000p TH-6AL-2Sn-4Z-6Mo TH-6AI-2S-Z6Mo-Si IMI 829 -IMI 834 Alpha 2 (TBAI) General Gamma (TIAI) General ---- INCONEL 718 O IMI 829 ROC A T-25A-1ONb-3V-IMo TI3AI ROC 100 10 28 30 32 34 36 38 40 Larsen-Miller parameter, P = (460'F + T°F)(20 + log 1 (h)] × 10 Stress (ksi)
Related questions
Question
![A Ti-6AI-2Sn-4Zr-6Mo titanium alloy subjected to a stress of 20 ksi. How long can the alloy be
used under this stress at 932 deg. F so that no more than 0.2% creep strain will occur.
1000
Ti-6AI-4V
Ti-6Al-2Sn-4Z1-6Mo
Ti-6A1-2S-4Z1-6Mo-Si
IMI 829
---- IMI 834
- Alpha 2 (Ti3AI) General
Gamma (TIAI) General
---- INCONEL 718
2 100
O IMI 829 ROC
A T-25AI-10Nb-3V-1Mo TI3AI ROC
28
30
32
34
36
38
40
Larsen-Miller parameter, P = (460'F + T°F)[20 + log 1 (h)] × 10~3
Stress (ksi)
10](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff83895e5-9155-4e3e-9d9d-65b995e15c49%2Fc1fc3fe2-2bad-4669-a756-780e6bfa0c15%2Fu0n0c2q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A Ti-6AI-2Sn-4Zr-6Mo titanium alloy subjected to a stress of 20 ksi. How long can the alloy be
used under this stress at 932 deg. F so that no more than 0.2% creep strain will occur.
1000
Ti-6AI-4V
Ti-6Al-2Sn-4Z1-6Mo
Ti-6A1-2S-4Z1-6Mo-Si
IMI 829
---- IMI 834
- Alpha 2 (Ti3AI) General
Gamma (TIAI) General
---- INCONEL 718
2 100
O IMI 829 ROC
A T-25AI-10Nb-3V-1Mo TI3AI ROC
28
30
32
34
36
38
40
Larsen-Miller parameter, P = (460'F + T°F)[20 + log 1 (h)] × 10~3
Stress (ksi)
10
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
