(a) The reverse saturation current of an npn-transistor, Is = 5.0 × 10-12 mA and the commonemitter current gain B = 125. The transistor is biased at VRE = 0.615 V . Calculate IR, Icand Ig.(b) The BJT circuit is shown in Fig. 1 (b). Plot the output load line by assuming that ß = 85and VBE (on) = 0.7 V.Vcc = 15 VRc = 0.5 k2RB = 28 kQVBR = 5 V o- WVBERe = 420 2Fig. 1(b)

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(a) The reverse saturation current of an npn-transistor, Is = 5.0 x 10-12 mA and the common emitter current gain ß = 125. The transistor is biased at VBE = 0.615 V . Calculate Ig, Ic and Ig- (b) The BJT circuit is shown in Fig. 1 (b). Plot the output load line by assuming that ß = 85 and VRE (on) = 0.7 V. Vcc = 15 V Rc = 0.5 k2 RB = 28 kN %3D VBB =5 V o- VBE RE = 420 2 Fig. 1(b)

(a) The reverse saturation current of an npn-transistor, Is = 5.0 x 10-12 mA and the common emitter current gain ß = 125. The transistor is biased at VBE = 0.615 V . Calculate Ig, Ic and Ig- (b) The BJT circuit is shown in Fig. 1 (b). Plot the output load line by assuming that ß = 85 and VRE (on) = 0.7 V. Vcc = 15 V Rc = 0.5 k2 RB = 28 kN %3D VBB =5 V o- VBE RE = 420 2 Fig. 1(b)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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