A common-emitter circuit using a BJT transistor (Figure 2a) is used to turn on a resistive load R2 = 2000, and supply 30 ma through it, when the input voltage V, at the input circuit is set to 5 V. When V, 0, the current through the resistive load should be cut off. Given B = 110, maximum current limit of the input voltage source is 6mA, and, Verser= 0.2V and Var- 0.7V when the transistor is saturated, calculate V, and the feasible range of R, for the circuit to function according to the above requirements. %3D R2 Va い1 R1

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(a)
A common-emitter circuit using a BJT transistor (Figure 2a) is used to turn on a
resistive load R, = 2000, and supply 30 ma through it, when the input voltage
V, at the input circuit is set to 5 V. When V, 0, the current through the resistive
load should be cut off. Given B = 110, maximum current limit of the input
voltage source is 6mA, and, Ersor = 0.2V and Vue= 0.7V when the transistor
is saturated, calculate V, and the feasible range of R, for the circuit to function
according to the above requirements.
%3D
!!
R2
R1
Figure 2a
Transcribed Image Text:(a) A common-emitter circuit using a BJT transistor (Figure 2a) is used to turn on a resistive load R, = 2000, and supply 30 ma through it, when the input voltage V, at the input circuit is set to 5 V. When V, 0, the current through the resistive load should be cut off. Given B = 110, maximum current limit of the input voltage source is 6mA, and, Ersor = 0.2V and Vue= 0.7V when the transistor is saturated, calculate V, and the feasible range of R, for the circuit to function according to the above requirements. %3D !! R2 R1 Figure 2a
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