(a) The common source amplifier is shown in Fig. 2(a) with the following circuit component values Rsi = 5 kN, Ccı = 0.1 µF, R = 180 kN, R, = 85 kn, Rs = 0.5 kN, Rp = 3 kn, and RL = 10 k. The MOSFET has AC small-signal parameters, gm = 50 mA/v, and ro = 00. %3D i. Find the lower corner frequency due to Cc1. ii. Design the amplifier circuit by considering the lower corner frequency is same due to CC1 and upper corner frequency, fu = 300 kHz. 2 iii. What is the bandwidth of the amplifier? iv. Determine the maximum gain of the designed amplifier in dB. v. What is the amplifier gain if Rs is bypassed by a large capacitance? VDD Rp R1 Rsi C RL 3: R2 Rs ww

(a) The common source amplifier is shown in Fig. 2(a) with the following circuit component values Rsi = 5 kN, Ccı = 0.1 µF, R = 180 kN, R, = 85 kn, Rs = 0.5 kN, Rp = 3 kn, and RL = 10 k. The MOSFET has AC small-signal parameters, gm = 50 mA/v, and ro = 00. %3D i. Find the lower corner frequency due to Cc1. ii. Design the amplifier circuit by considering the lower corner frequency is same due to CC1 and upper corner frequency, fu = 300 kHz. 2 iii. What is the bandwidth of the amplifier? iv. Determine the maximum gain of the designed amplifier in dB. v. What is the amplifier gain if Rs is bypassed by a large capacitance? VDD Rp R1 Rsi C RL 3: R2 Rs ww

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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