A symmetrical vertical summit curve has tangents of +4% and -2%. The allowable change of grade is 0.3% per meter station. Stationing and elevation of P.T. is at 10+020 and 142.63 respectively. 1. Compute the length of curve. 2. Compute the distance of the highest point of the curve from the P.C. 3. Compute the elevation of the highest point of the curve.

Q: A vertical summit curve has tangent grades of +2.8% and -1.6%. The curve will be designed such that…

A:

Q: Vertical Curve: If L=1320 ft, the BVC is at 5+00, What is the Station and Elevation for PVI ? G1 is…

A:

Q: A symmetrical parabolic curve passes through point A whose elevation is 23.23m at a distance meters…

A: Using equation y=g2-g12Lx2+g1x+PVCelvg1=back tangentg2=Forward tangentL=length

Q: Problem 4 A vertical summit parabolic has its P.I. at station 12 + 750 with elevation of 77.30 m.…

A: Given Data:Station of PV1=12+750Elevation Pv1=77.30mForward Tangent g2=-3.8%back tangent…

Q: An asymmetrical vertical parabolic curve has a forward descending grade of 4% and backward ascending…

A:

Q: A grade g1 of +3.25% intersects grade g2 of -2.75% at a vertex whose station and elevation are…

A: The Point of Vertical Curvature (PVC) is the point where the curve starts. It is located at a…

Q: A vertical summit curve is having tangents which intersects at point Pl at Station 12+617.78 and…

A: PVCstn=PVIStn-L212506.53=12617.78-L2=222.5MPVCelv=PVIelv-g1L2123.37=134.19-g1×222.52g1=0.0972×100g1=…

Q: SITUATION 8: A parabolic sag curve has tangent grades of -2% and +3%. The stationing of PT is at…

A:

Q: Given a crest curve with slopes p=+3.0% and q= -2.0%, Station of PI= 4+350 and elevation of PI…

A:

Q: It is required to construct a vertical curve with 400m from the PC at STA 3+16, elev.214m to the…

A:

Q: Given two grades intersecting at station 1 + 250m, one grade at +6%, the other at -3%. Use a…

A: Given data, Two grade intersecting at station 1+250m g1=+6% and g2=-3% L=183m L1=121.95m and…

Q: Given a sag curve with slopes p= -3.0% and q= 2.0%, Station of PI= 4+350 and elevation of PI…

A: Sag vertical curves are curves that connect descending grades, forming a sag. It's designing similar…

Q: evel and the through chainage of the intersection point of the two gradients are 93.60m and 66…

A: PVCSTATION=PVISTA-L2PVCsta=6671.34-2002=6571.34PVCELV=PVIELV-g1L2PVCelv=93.6-0.01×2002PVCelv=92.6

Q: The length of a parabolic sag curve is 126 meters. The curve's tangent grades are -2% and 3%,…

A:

Q: PI Elevation 81 82 PC Elevation What is the total length of the curve in meters consider the…

A: G1 = 6.82% G2 = -2.38%

Q: ration of the P.C. at station 4+100 is 22.5 e length of the curve is 120m.. Determin

A:

Q: 4) Vertical Curves Design the vertical curve for every 50 foot station if ... PVI is at11+02.43 PVI…

A: Given:- The incoming grade of curve = +6% The outgoing grade of curve = -2% The stationing of point…

Q: A 669m equal tangent crest vertical curve has PVC at Sta 18+662 and at elevation 199m. The initial…

A: Given- PVCSTA=18+662E=199mn1=7.25%n2=-7.42%L=669m

Q: A 3% ascending grade meets a 5% descending grade at station 2+110 and elevation 100m. The tangents…

A:

Q: A vertical crest curve has an approach grade +3% and a departure grade –3%. The VIP level is 120 m…

A: To calculate 'H' based on the given data we have  2HL2= (g1 -g2)L2L g1 = 3% = 0.03 g2 = -3% = - 0.03…

Q: The rate of change of the grade of a parabolic summit curve is 0.5%. The grade of ascending and…

A: According to given data -The rate of change of the grade of a parabolic summit curve is 0.5%. The…

Q: locate both highest and lowest point in terms of horizontal distance from PVT station and difference…

A: Of location of  both highest and lowest point in terms of horizontal distance from PVT station and…

Q: design the curve at 20 metres intervals.

A: Solution: Givendata, K = 50. G1 = +3.6 G2 = –2.2 Chainage of B = 2909.466 RL of B = 38.689 m Curve…

Q: A parabolic curve has a descending grade of -0.6% which meets an ascending grade of 0.3% at sta. 10…

A:

Q: Compute the ruling minimum radius of horizontal curve for a design speed of 80 kph, f = 0.15 and e =…

A: Hello dear this is the solution of your problem Radius of horizontal curve is found to be  R=232m…

Q: 2. A vertical parabolic curve is designed to pass thru three points on the proffle of an cxisting…

A:

Q: A 1600-ft-long equal tangent sag vertical curve has the PVI at station 120+00 and elevation…

A: Given:- PVI station = 120+00 Elevation = 1500 ft Initial grade =-3.5% Final grade =+6.5% To find:-…

Q: 2. Vertical Curve Given the following vertical curve data, compute the elevations of the curve,…

A: Given: Given the following vertical curve data             g1= -1%, g2 = 1.5%, L=100m, PVI at 2+200,…

Q: -3% grade is connected to a +1.2% grade by means of 200 m vertical curve. The PJ station is 100+ 00…

A:

Q: 6. A symmetrical vertical summit curve has tangents of +4% and -2%. The allowable rate of change of…

A:

Q: The forward and backward tangent grades of the symmetrical ve respectively. The elevation of the…

A: We knowPVCelv=PVIelv+g1L2PVTelv=PVIelv+g2L2PVCelv-PVTelv=L2g1-g298.134-100.534=L20.06+0.04L=48m

Q: It is required to construct a vertical curve with 400m from the PC atS TA 3+16, elev.214m to the…

A: A station is a precise location on the Earth that has been identified by surveying procedures.…

Q: It is required to construct a vertical curve with 400m from the PC at STA 3+16, elev.214m to the…

A: