1.The forward and backward tangent grades of the symmetrical vertical parabolic curve are +6% and -4%respectively. The elevation of the beginning of the curve is 98.134m and the elevation of the end of the curve is100.534m.a) Compute the length of the curve.b) Compute the rate of change.c) Compute for the elevation of S.

We knowPVCelv=PVIelv+g1L2PVTelv=PVIelv+g2L2PVCelv-PVTelv=L2g1-g298.134-100.534=L20.06+0.04L=48m

The forward and backward tangent grades of the symmetrical ve respectively. The elevation of the beginning of the curve is 98.134m 100.534m. a) Compute the length of the curve. b) Compute the rate of change. c) Compute for the elevation of S

The forward and backward tangent grades of the symmetrical ve respectively. The elevation of the beginning of the curve is 98.134m 100.534m. a) Compute the length of the curve. b) Compute the rate of change. c) Compute for the elevation of S

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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