A reversed curve is connecting the two tangent lines AB and CD having directions of due East and S 60° E. respectively. The radius of the first curve at A (P.C.) Is 200 m. and that of the second curve at D (PT) is 400 m. Stationing of A (P.C.) is at 10 + 120.50. IED is 300 m. long and has a bearing of S 20° E. Find the stationing of PT. O 10+597.70 O 10+599.70 O 10+577.70 O 10+579.70