Answered: Given two grades intersecting at…

Given two grades intersecting at station 1 + 250m, one grade at +6%, the other at -3%. Use a vertical curve of 183m composed of two

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A 160m long parabolic curve connects a -8% grade to a +2% grade. These grades intersect at Sta.…

Q: 23.15 A +4% grade intersects a -3% grade at station 3+ 000m at elevation 566.98 m. Compute the…

A: PVCSTATION=PVISTA-L2PVCsta=3000-6002=2+700PVCELV=PVIELV-g1L2PVCelv=566.98-0.04×6002PVCelv=554.98m

Q: 3.) A -4% grade meets a 7% grade at station 2 + 185 of elevation 150 m. The lengths are L1 = 70 m.…

A: Downward gradient=-4% Upward gradient=7% Elevation=150 m L1=70 m, L2=50 m.

Q: The tangents of a sag curve connects at the point of intersection having Station 18+407.60 and…

A: 1. Given : At point of intersection (PI) ⇒ Station = 18 + 407.60…

Q: A 7% descending grade intersects an 9% ascending grade at the vertex, V, at station 1+ 100 having an…

Q: An equal-tangent sag vertical curve on a section of a highway connects an initial grade of -2% and a…

Q: A grade of -5% grade intersects a grade of 0%. P.C. has a STATION of 10 + 110.00 which has an…

A: Given that Sag vertical curve g1 = -5% g2 = 0 A = G1-G2 A = -5 PC station = (10+110)…

Q: A forward tangent of +6% was designed to intersect a back tangent of -3% at a proposed underpass…

A: GIVEN DATA:- L1 = 200m L2 = 100m g1 = -3% g2= +6% VPI 12+ 530.20 Bridge Elevation = 117.48m VPI…

Q: A +3% grade intersects a -2% grade at STA 4+350 meter at an elevation of 190.50 meter. Given that a…

A: The backward grade, g1 = +3%the forward grade, g2 = -2%The Station of point of vertical…

Q: A +0.7% grade meets a -0.4% grade at sta 2+700 and at elevation 30 m. The max allowable change in…

A: Given information, n1 = 0.7%n2 = -0. 4%Maximum allowable change in grade/sta.=0.2%

Q: The elevation of PT is at elevation 454.50m while the lowest point on the curve is located 40m from…

Q: A symmetrical parabolic summit curve is to connect two roads with grades of +4% and -2.5% that meet…

A: G1 = 4% G2 = -2.5%

Q: A -4% grade at Sta. 5 + 700 and elev. 110.2 is to connect to a +6% grade at Sta. 6 + 100 and elev.…

A: G1 = -4% , BVC, station = 5+700 , elevation = 110.2 G1 = +6% , EVC,…

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (53+50) with elevation…

A: given- R.L of A= (1271.2 m) at station (53+50)back grade g1= (-4%) forward grade g2= (+3.8%)(PVI)…

Q: Compute the elevation and station of the highest point of the following vertical curve. 320-m…

A: Given, L = 320 mn1 = 2 %n2 = -1.6 %

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation…

A: Given: The station of lower point A is 55+50. The elevation of A is 1291.2 m. The back grade is -6%.…

Q: An equal tangent vertical curve is to be constructed between grades of -6.75% (initial) and 4.75%…

A: G1= -6.75% G2= 4.75%PVI station = 12+000.000 PVI elevation = 319m Station = 12 + 071.00 Elevation =…

Q: A-4% grade line meets another line of +3.2% grade at station 11+ 40. If a 225-ft parabolic curve…

A: This question is related to Simple curve from Surveying Engineering. In this question we calculate…

Q: 23.1 A 1,500-ft vertical curve is to be used for joining a +3.0% grade line and a-4.0% grade line.…

A: The length of curve, L= 1500 ftThe grade of upgrade, g1 = +3%The grade of downgrade, g2 = -4%The…

Q: vertical parabolic curve is to be used as a grade-separation structure. The curve is 231 m long and…

Q: A vertical parabolic curve is to be used as a grade-separation structure. The curve is 242 m long…

A: Here's the calculation: First, we need to find the parabolic constant (K) using the formula: K = (G2…

Q: A plus 2.8% grade elevation intersects a minus 5.1% grade at station 2 + 087.224 at an elevation of…

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation…

A: g1 = -6% g2 = +5.8% Station at PVI = 54+00 Elevation of PVI = 1281.5m At point A - Station A - 55+50…

Q: A vertical summit curve connects a +6% grade to a -3% grade at Pl at station 150+ 00 whose elevation…

A: Answer (a) Calculation of Length of vertical curve needed to make the highest point at station 150…

Q: EXAMPLE A -2% grade meets a +8% gradę near an underpass. In order to maintain the minimum clearance…

Q: Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation…

Q: A -6% grade is followed by a 2% grade intersecting at Sta. 15+750, with an elevation of 372.25 m.…

Q: A 4.5% grade intersects a -1% grade at STA 5+180 at an elevation of 195m. A vertical curve of length…

A: Given: The length of vertical curve is 120 m. Here: PVC Station=PVI Station- Length of vertical…

Q: Prob. 3. A forward tangent of +6% was designed to intersect a back tangent of -3% at a proposed…

A: You can determine tangent length by calculating the central angle of the curve, in degrees. An angle…

Q: A parabolic vertical curve joins a grade of -2.0% to a grade of 0.5%. The point of intersection of…

A: Soution: d = 390-300 = 90 m Eleve = 100-4 = 96 m Elevf = 0.5% of 90 = 0.45 Elevg = 2% of 90=1.8

Q: A vertical symmetrical sag curve has a descending grade of - 4.2% and an ascending grade of +3%…

Q: Two tangents intersect at V with back tangent having a grade of -4% and forward tangent of 5%. A 205…

Q: A vertical equal-tangent, 100O ft long, connects an initial grade of -2.5% and a final grade of +2%.…

Q: A vertical parabolic curve of length 180m has the following specifications. The point of interaction…

A: Vertical curves are utilized to give continuous change between two adjoining vertical grade lines.…

Q: An equal tangent crest curve connects a +2% initial grade with a -1% final grade, and is designed…

A: Grade: G1 = 2% Grade: G2 = -1% Design speed: V = 55 mi/h Station at PVI: = 233+40 Elevation of PV:=…

Q: An equal-tangent sag vertical curve on a section of a highway connects an initial grade of -2% and a…

A: g1 = initial grade = -2%g2 = final grade = +3.5%PVISTA = Stationing of EVC = 25 + 00yPVI = Elevation…

Concept explainers

Structural components of framed construction

It is a rigid and stable framework of structures that consists of structural members like slabs, beams, and columns that can resist the deformation due to the self-weight and high external loads and transfer the applied loads safely to the substructure and consecutively to the ground. It is made of different materials, such as reinforced concrete, steel, and wood. In ancient days, load-bearing structures were used to build houses and houses were built using load-bearing walls.

Question

Given two grades intersecting at station 1 + 250m, one grade at +6%, the other at -3%. Use a vertical curve of 183m composed of two sections, L1 of 121.95m and L2 of 61.05m. Find the elevation on the curve at station 1 + 220 and at station 1 + 280.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Structural components of framed construction

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

23.17 A -5% slope meets a +3% grade at elevation 548.97 ft at station 43 +00. Assuming a 1000-ft vertical curve, determine the elevation on the curve at each 100- ft station and find the station and elevation at the low point on the curve. (Ans.: Low point at 44 +25, elevation 558.34 ft)
Two tangents intersect at V with back tangent having a grade of -4.5% and forward tangent of 5.5%. A 200 m curve lies on the side of PC and 102.5 on the other side. Stationing of V is at 10+538 having an elevation of 104 m. If a bridge is located above the curve, with its centerline having an elevation of 118.5 m and stationing of 10+555, with underside of the bridge located 55 cm below the given elevation, determine the height of highest vehicle it can accommodate if the bridge has a width of 12 m.
A highway curve will pass through a railway and grade. The crossing must be at station 4 + 310 and at elevation 220 3.38 m. the initial grade is + 2% and meets a -3% grade at station 4 + 235 at an elevation of 223.38 m. the rate of change must not exceed at 2%. Compute the length of curve, station and elevation of highest point also check if the condition of rate of change is meet.
Q3/ A vertical curve below has a lower point (A) which exists at station (55+50) with elevation (1291.2 m). the back grade of (-8%) meet the forward grade of (+7.8%) at (PVI) station (54+00) with elevation (1281.5 m). determine the length of the curve with the stations of (PVC) and (PVT)? PVT PVC g₁=(-6%) PVI g₂=(+5.8%)
A -3% grade intersects a +2% grade at STA 4+350 meter at an elevation of 200.00 meter. Given that a 250 meter symmetrical parabolic curve is used, find, draw and plot the elevation of the curve at every 20 meter interval starting at STA 4+240 meter including its critical point
A symmetrical parabolic summit curve connects two grades of +6% and -4%. It is to pass though a point "P" the stationing of which is 35+280 and the elevation is 193.13 meters. If the elevation of the grade intersection is 200 m with stationing 35 + 300. 1. What is the length of the curve? a. 120 m b. 123 m c. 121 m d. 122 m
3.9 An equal-tangent crest curve connects a +2% initial grade with a -1% final grade, and is designed for 55 mi/h. The station of the PVI is 233 + 40 with elevation 1203 ft. What is the elevation of the curve at station 234 +00?
A -4% grade line meets another line of +3.2% grade at station 11+ 4O. If a 225-ft parabolic curve connects these grade lines, at what station is the lowest point along the curve located? Your answer
2. A symmetrical sag curve has a descending grade of -4.2% and an ascending grade of +2.5% intersecting at Station 10+120, whose elevation is 382.3÷4 m. The rate of change of grade is restricted to 0.60%. a. What is the vertical offset of the parabolic curve to the point of intersection of the tangent grades? b. At what distance from PC is the lowest point of the curve located?
A 5.3% grade intersects a -1.9% grade at STA 5+180 at an elevation of 186m. A vertical curve of length 120m is to be run forward from the point of intersection, and a curve of length 80m is to be extended back forming an unsymmetrical curve. Determine the elevation (m) of the curve below PVI.
A grade of -3.6% is followed by a grade of +2.1% which intersects at station 10+256 and elevation of 116 m. If the maximum change in grade per 20 m station is 0.20%, determine the following A. Length of parabolic curve that shall connect these two grade lines. B. Elevation of PC. C. Elevation of a point on the curve @ Sta.10+250.