Problem 4 A vertical summit parabolic has its P.I. at station 12 + 750 with elevation of 77.30 m. The grade of the back tangent is 2.4 % and forward tangent of -3.8%. If the length of curve is 400 m. 1. Compute the location of the vertical curve turning point from the P.I. 2. Compute the elevation of the vertical curve turning point in meters. 3. Compute the stationing of the vertical curve turning point.

Q: Vertical Curve: If L=1320 ft, the BVC is at 5+00, What is the Station and Elevation for PVI ? G1 is…

A:

Q: A symmetrical parabolic curve passes through point A whose elevation is 23.23m at a distance meters…

A: Using equation y=g2-g12Lx2+g1x+PVCelvg1=back tangentg2=Forward tangentL=length

Q: to 0.5%. gth of curve.

A: Length :L=Ar=(1.5+3)0.5×100=900m

Q: Problem 2 A symmetrical vertical summit curve has tangents of +5% and -3%. The allowable rate of…

A:

Q: (CE 2015). A slmple curve having a radius of 200 meters having a tangent with bearing N 10 deg E and…

A:

Drainage of Pavements

Pavement Drainage holds ample significance, as it prevents the accumulation of water or any liquid on the surface of pavements and ensures proper drainage system. With proper design and gradual slopes provided, the water gets easily removed from the surface into the drains, which are essential during heavy rains and unusual weather conditions keeping it less prone to accidents and increasing the durability of the pavement structure.