A substitution reaction is carried out on 2-iodobutane with sodium halide in alcohol solvent at 25°C, as follows: CH3CH2-CH(I)-CH3 + Nax Br or Cl) -(alcohol)-------> CH3CH2-CH(X)-CH3 + Nal (X = Based on the following observations, what is the most likely mechanism of this reaction? 1. The reaction rate is the same for NaCI and NaBr. 2. 2-methyl-2-iodobutane reacts faster with Nax under the same solvent/temperature conditions (mechanism is same as the 2-iodobutane reaction). Select one: A. A two-step substitution mechanism in which the 2nd step is slow and rate- determining. B. SN2 C. A two step mechanism in which X- bonds to C (bearing I) in step 1, followed by loss of I in step 2. D. SN1
A substitution reaction is carried out on 2-iodobutane with sodium halide in alcohol solvent at 25°C, as follows: CH3CH2-CH(I)-CH3 + Nax Br or Cl) -(alcohol)-------> CH3CH2-CH(X)-CH3 + Nal (X = Based on the following observations, what is the most likely mechanism of this reaction? 1. The reaction rate is the same for NaCI and NaBr. 2. 2-methyl-2-iodobutane reacts faster with Nax under the same solvent/temperature conditions (mechanism is same as the 2-iodobutane reaction). Select one: A. A two-step substitution mechanism in which the 2nd step is slow and rate- determining. B. SN2 C. A two step mechanism in which X- bonds to C (bearing I) in step 1, followed by loss of I in step 2. D. SN1
Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Substitution Reaction Mechanism in Organic Chemistry**
When exploring substitution reactions, consider the example of a reaction carried out on 2-iodobutane with sodium halide in an alcoholic solvent at 25°C:
\[ \text{CH}_3\text{CH}_2\text{-CH(I)-CH}_3 + \text{NaX} \quad \xrightarrow{\text{(alcohol)}} \quad \text{CH}_3\text{CH}_2\text{-CH(X)-CH}_3 + \text{NaI} \]
(where \( \text{X} = \text{Br or Cl} \))
### Observations:
1. **Rate of Reaction**: The reaction rate remains unchanged for both NaCl and NaBr.
2. **Reactivity**: 2-methyl-2-iodobutane reacts more rapidly with NaX under identical solvent and temperature conditions, using a mechanism analogous to the 2-iodobutane reaction.
### Question:
What is the most likely mechanism for this reaction, based on the observed data?
**Options**:
- **A.** A two-step substitution mechanism where the second step is slow and rate-determining.
- **B.** \( S_N2 \) mechanism.
- **C.** A two-step mechanism in which \( \text{X}^- \) bonds to the carbon atom bearing iodine in the first step, succeeded by the loss of iodine in the second step.
- **D.** \( S_N1 \) mechanism.
Evaluate the options to determine the most plausible mechanism considering the effects of substrate structure, the leaving group, and the nature of the nucleophile involved.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7b7ae93-49f4-4302-b4e6-fcebec551689%2F4e546102-b121-445e-b349-26a157979f14%2F1n81t1zb_processed.png&w=3840&q=75)
Transcribed Image Text:**Substitution Reaction Mechanism in Organic Chemistry**
When exploring substitution reactions, consider the example of a reaction carried out on 2-iodobutane with sodium halide in an alcoholic solvent at 25°C:
\[ \text{CH}_3\text{CH}_2\text{-CH(I)-CH}_3 + \text{NaX} \quad \xrightarrow{\text{(alcohol)}} \quad \text{CH}_3\text{CH}_2\text{-CH(X)-CH}_3 + \text{NaI} \]
(where \( \text{X} = \text{Br or Cl} \))
### Observations:
1. **Rate of Reaction**: The reaction rate remains unchanged for both NaCl and NaBr.
2. **Reactivity**: 2-methyl-2-iodobutane reacts more rapidly with NaX under identical solvent and temperature conditions, using a mechanism analogous to the 2-iodobutane reaction.
### Question:
What is the most likely mechanism for this reaction, based on the observed data?
**Options**:
- **A.** A two-step substitution mechanism where the second step is slow and rate-determining.
- **B.** \( S_N2 \) mechanism.
- **C.** A two-step mechanism in which \( \text{X}^- \) bonds to the carbon atom bearing iodine in the first step, succeeded by the loss of iodine in the second step.
- **D.** \( S_N1 \) mechanism.
Evaluate the options to determine the most plausible mechanism considering the effects of substrate structure, the leaving group, and the nature of the nucleophile involved.
![**Question:**
What is the organic product that forms in the following S<sub>N</sub>2 reaction?
**Reaction Diagram:**
- A linear molecule with a bromine (Br) and hydrogen (H) attached to a central carbon atom reacts with water (H<sub>2</sub>O) under S<sub>N</sub>2 conditions.
**Product Options:**
- Four structural isomers are provided as possible products:
**I.**
- A three-carbon chain with the hydroxyl (OH) group attached to the second carbon. Both hydrogens on that carbon are shown.
**II.**
- A three-carbon chain with the hydroxyl (OH) group attached to the first carbon (terminal carbon).
**III.**
- A similar structure to the reactant but with the hydroxyl (OH) group instead of the bromine (Br) on the second carbon.
**IV.**
- A three-carbon chain with the hydroxyl (OH) group also on a terminal carbon.
**Answer Options:**
- Select one:
- A. I
- B. II
- C. IV
- D. III](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7b7ae93-49f4-4302-b4e6-fcebec551689%2F4e546102-b121-445e-b349-26a157979f14%2F7rcq2ns_processed.png&w=3840&q=75)
Transcribed Image Text:**Question:**
What is the organic product that forms in the following S<sub>N</sub>2 reaction?
**Reaction Diagram:**
- A linear molecule with a bromine (Br) and hydrogen (H) attached to a central carbon atom reacts with water (H<sub>2</sub>O) under S<sub>N</sub>2 conditions.
**Product Options:**
- Four structural isomers are provided as possible products:
**I.**
- A three-carbon chain with the hydroxyl (OH) group attached to the second carbon. Both hydrogens on that carbon are shown.
**II.**
- A three-carbon chain with the hydroxyl (OH) group attached to the first carbon (terminal carbon).
**III.**
- A similar structure to the reactant but with the hydroxyl (OH) group instead of the bromine (Br) on the second carbon.
**IV.**
- A three-carbon chain with the hydroxyl (OH) group also on a terminal carbon.
**Answer Options:**
- Select one:
- A. I
- B. II
- C. IV
- D. III
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