A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Proctored Nonproctored μ μ1 μ2 n 32 33 x 75.91 88.05 s 10.92 18.37 a. Use a 0.01 significance level to test the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. What are the null and alternative hypotheses? A. H0: μ1=μ2 H1: μ1≠μ2 B. H0: μ1=μ2 H1: μ1>μ2 C. H0: μ1≠μ2 H1: μ1<μ2 D. H0: μ1=μ2 H1: μ1<μ2 The test statistic, t, is negative 3.28−3.28. (Round to two decimal places as needed.) The P-value is 0.00010.0001. (Round to three decimal places as needed.) State the conclusion for the test. A. Fail to reject H0. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. B. Reject H0. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. C. Fail to reject H0. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. D. Reject H0. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. b. Construct a confidence interval suitable for testing the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. 22.1422.14<μ1−μ2
A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Proctored Nonproctored μ μ1 μ2 n 32 33 x 75.91 88.05 s 10.92 18.37 a. Use a 0.01 significance level to test the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. What are the null and alternative hypotheses? A. H0: μ1=μ2 H1: μ1≠μ2 B. H0: μ1=μ2 H1: μ1>μ2 C. H0: μ1≠μ2 H1: μ1<μ2 D. H0: μ1=μ2 H1: μ1<μ2 The test statistic, t, is negative 3.28−3.28. (Round to two decimal places as needed.) The P-value is 0.00010.0001. (Round to three decimal places as needed.) State the conclusion for the test. A. Fail to reject H0. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. B. Reject H0. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. C. Fail to reject H0. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. D. Reject H0. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. b. Construct a confidence interval suitable for testing the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. 22.1422.14<μ1−μ2
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from
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Proctored
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Nonproctored
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μ
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μ1
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μ2
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n
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32
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33
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x
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75.91
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88.05
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s
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10.92
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18.37
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a. Use a
mean score than those taking proctored tests.
0.01
significance level to test the claim that students taking nonproctored tests get a higher What are the null and alternative hypotheses?
H0:
μ1=μ2
H1:
μ1≠μ2
H0:
μ1=μ2
H1:
μ1>μ2
H0:
μ1≠μ2
H1:
μ1<μ2
H0:
μ1=μ2
H1:
μ1<μ2
The test statistic, t, is
negative 3.28−3.28.
(Round to two decimal places as needed.)The P-value is
0.00010.0001.
(Round to three decimal places as needed.)State the conclusion for the test.
Fail to reject
H0.
There
is
sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests.Reject
H0.
There
is not
sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests.Fail to reject
H0.
There
is not
sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests.Reject
H0.
There
is
sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests.b. Construct a confidence interval suitable for testing the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests.
22.1422.14<μ1−μ2<negative 2.14−2.14
(Round to two decimal places as needed.)
Does the confidence interval support the conclusion of the test?
No,
Yes,
No,
only negative values.
only positive values.
only negative values.
zero.
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