e HomeTreatment Placebo1 of 1H2A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples areindependent simple random samples selected from normally distributed populations, and do not assume that the population standarddeviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts.uncementsn25372.382.621 of oo80Xgnments0.960.65dy Plan1 of 1O A. Ho: H1# H2B. Ho: H1 = H2debookH1: 41 # H2O C. Ho: H1 = H2O D. Ho: H1< H21 of 2atCrunchHq: Hy> H2Text1 of 2The test statistic, t, is(Round to two decimal places as needed.)Chapter ContentsThe P-value is(Round to three decimal places as needed.)0 of 1Tools for SuccessState the conclusion for the test.Multimedia LibraryO A. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the two samples are from populations with the samemean.Purchase OptionsO B. Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same mean.OC. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same mean.Course ToolsO D. Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same mean.DiscussionsClick to select your answer(s).?LIT2090 Term Pa...pdfDEC4.PAGES1214292,349W80888F3DIIDDF4F5F6F7F8F9F1024%346080QETY. Course HomeTreatment Placebo1 of 1see scoreAnnouncementsA study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples areindependent simple random samples selected from normally distributed populations, and do not assume that the population standarddeviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts.H1H22537Assignments1 of oo2.382.62see scoreS0.960.65Study PlanO D. Ho: H1 H21 of 1see scoreGradebookThe test statistic, t, is(Round to two decimal places as needed.)StatCrunch1 of 2see scoreThe P-value is(Round to three decimal places as needed.)еТеxtState the conclusion for the test.1 of 2see scoreChapter ContentsO A. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the two samples are from populations with the samemean.Tools for Success0 of 1B. Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same mean.Multimedia LibraryC. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the clan that the two samples are from populations with the same mean.D. Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same mean.Purchase Optionsb. Construct a confidence interval suitable for testing the claim that the two samples are from populations with the same mean.Course Tools

Answered: Treatment Placebo A study was done…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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e Home
Treatment Placebo
1 of 1
H2
A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are
independent simple random samples selected from normally distributed populations, and do not assume that the population standard
deviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts.
uncements
n
25
37
2.38
2.62
1 of oo
80
X
gnments
0.96
0.65
dy Plan
1 of 1
O A. Ho: H1# H2
B. Ho: H1 = H2
debook
H1: 41 # H2
O C. Ho: H1 = H2
O D. Ho: H1< H2
1 of 2
atCrunch
Hq: Hy> H2
Text
1 of 2
The test statistic, t, is
(Round to two decimal places as needed.)
Chapter Contents
The P-value is
(Round to three decimal places as needed.)
0 of 1
Tools for Success
State the conclusion for the test.
Multimedia Library
O A. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same
mean.
Purchase Options
O B. Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same mean.
OC. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same mean.
Course Tools
O D. Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same mean.
Discussions
Click to select your answer(s).
?
LIT2090 Term Pa...pdf
DEC
4.
PAGES
12
1429
2,349
W
80
888
F3
DII
DD
F4
F5
F6
F7
F8
F9
F10
24
%
3
4
6
080
Q
E
T
Y.

Course Home
Treatment Placebo
1 of 1
see score
Announcements
A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are
independent simple random samples selected from normally distributed populations, and do not assume that the population standard
deviations are equal. Complete parts (a) and (b) below. Use a 0.10 significance level for both parts.
H1
H2
25
37
Assignments
1 of oo
2.38
2.62
see score
S
0.96
0.65
Study Plan
O D. Ho: H1 <H2
H1:H1> H2
1 of 1
see score
Gradebook
The test statistic, t, is
(Round to two decimal places as needed.)
StatCrunch
1 of 2
see score
The P-value is
(Round to three decimal places as needed.)
еТеxt
State the conclusion for the test.
1 of 2
see score
Chapter Contents
O A. Fail to reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same
mean.
Tools for Success
0 of 1
B. Reject the null hypothesis. There is sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same mean.
Multimedia Library
C. Fail to reject the null hypothesis. There is sufficient evidence to warrant rejection of the clan that the two samples are from populations with the same mean.
D. Reject the null hypothesis. There is not sufficient evidence to warrant rejection of the claim that the two samples are from populations with the same mean.
Purchase Options
b. Construct a confidence interval suitable for testing the claim that the two samples are from populations with the same mean.
Course Tools
<H1 -H2<
(Round to three decimal places as needed.)
Discussions
Click to select your answer(s).
LIT2090 Term Pa..pdf
Show All
DEC
12
1429
2,349
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F4
F5
DII
F6
F7
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Expert Solution

Step 1

$G i v e n α = s i g n i f i c a n c e l e v e l = 0.10 F o r T r e a t m e n t g r o u p : μ_{1} = p o p u l a t i o n m e a n t r e a t m e n t g r o u p n_{1} = s a m p l e s i z e f o r t r e a t m e n t g r o u p = 25 {\bar{x}}_{1} = s a m p l e m e a n f o r t r e a t m e n t g r o u p = 2.38 s_{1} = s a m p l e s \tan d a r d d e v i a t i o n f o r t r e a t m e n t g r o u p = 0.96 F o r P l a c e b o g r o u p : μ_{2} = p o p u l a t i o n m e a n p l a c e b o g r o u p n_{2} = s a m p l e s i z e f o r p l a c e b o g r o u p = 37 {\bar{x}}_{2} = s a m p l e m e a n f o r p l a c e b o g r o u p = 2.62 s_{2} = s a m p l e s \tan d a r d d e v i a t i o n f o r p l a c e b o g r o u p = 0.65$

The population standard deviations are not equal $(σ_{1} \neq σ_{2})$ .

Step 2

$T h e n u l l a n d a l t e r n a t i v e h y p o t h e s i s : H_{0} : μ_{1} = μ_{2} H_{1} : μ_{1} \neq μ_{2} T h i s i s t w o t a i l e d t e s t .$

Step 3

$T e s t s t a t i s t i c : t = \frac{{\bar{x}}_{1} - {\bar{x}}_{2}}{\sqrt{(\frac{{s_{1}}^{2}}{n_{1}} + \frac{{s_{2}}^{2}}{n_{2}})}} ~ t d i s t r i b u t i o n w i t h d f = s m a l l e r (n_{1} - 1, n_{2} - 1) = \frac{2.38 - 2.62}{\sqrt{(\frac{0 . 96^{2}}{25} + \frac{0 . 65^{2}}{37})}} = - 1.09 D e g r e e o f f r e e d o m : d f = s m a l l e r (n_{1} - 1, n_{2} - 1) = s m a l l e r (25 - 1, 37 - 1) = 24$

Step 4

$p - v a l u e : p - v a l u e = 0.287 (b y u \sin g p - v a l u e c a l c u l a t o r) p - v a l u e > α$

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