done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard d qual. Complete parts (a) and (b) below. Use a 0.01 significance level to test the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. what are the null and alternative hypotheses? DA Ho: =P2 OB. Ho: P "P2 OC. Ho H 2 OD. H: =P The test statistic, t, is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) State the conclusion for the test. OA. Fail to reject Hg. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. OB. Reject Hg. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. OC. Reject Hg. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. O D. Fail to reject Hg. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. . Construct a confidence interval suitable for testing the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. Round to two decimal places as needed.) Does the confidence interval support the conclusion of the test? V because the confidence interval contains
done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard d qual. Complete parts (a) and (b) below. Use a 0.01 significance level to test the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. what are the null and alternative hypotheses? DA Ho: =P2 OB. Ho: P "P2 OC. Ho H 2 OD. H: =P The test statistic, t, is (Round to two decimal places as needed.) The P-value is (Round to three decimal places as needed.) State the conclusion for the test. OA. Fail to reject Hg. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. OB. Reject Hg. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. OC. Reject Hg. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. O D. Fail to reject Hg. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. . Construct a confidence interval suitable for testing the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. Round to two decimal places as needed.) Does the confidence interval support the conclusion of the test? V because the confidence interval contains
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A study was done on proctored and nonproctored tests. The results are shown in the table. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are
equal. Complete parts (a) and (b) below.
Proctored Nonproctored
H1
H2
33
30
74.26
84.67
S
11.53
19.01
a. Use a 0.01 significance level to test the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests.
What are the null and alternative hypotheses?
O A. Ho: H1 = H2
O B. Ho: H1 = H2
H,: Hy> H2
OC. Ho: H1 H2
H1: 41 <H2
D. Ho: H1 = H2
H1: 41 <H2
The test statistic, t, is. (Round to two decimal places as needed.)
The P-value is . (Round to three decimal places as needed.)
State the conclusion for the test.
A. Fail to reject Ho. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests.
B. Reject Ho. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests.
C. Reject Ho. There is sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests.
D. Fail to reject Ho. There is not sufficient evidence to support the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests.
b. Construct a confidence interval suitable for testing the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests.
-H2
(Round to two decimal places as needed.)
Does the confidence interval support the conclusion of the test?
because the confidence interval contains
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