A study touna that 41% of the assisted reproductive technology (ART) cycies resulted in pregnancies Twenty-eight percent of the ART pregnancies esuted in mutple tirms(a) Find the probability that a random selected ART cycle tesulted in a pregnancy and produced a multiple birth(b) Find the probatility that a randomly selected ART cycle that resuted in a pregnancy did not produce a mutipie birth(C) Would it be unusual for a randomy selected ART cycle to resut in a pregnancy and produce a mutiple birth? Explain(a) The probabilty that a randomly selected ART cycle resuted in a pregnancy and produced a multiple tirm(Round to the nearest thousandth as needed.)

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Answered: A study tound that 41% of the assisted…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Which of the following statements about the False Discovery Rate (FDR) is correct? The FDR is the only method available for controlling multiple testing error in transcriptional profiling data The FDR cutoff value should be held to the same standard as the p-value cutoff when doing hypothesis testing The FDR can be interpreted as meaning “the proportion of the significant gene list one would expect to find significant by chance due to the multiple testing error” The FDR greatly simplifies analysis, allowing researchers to add many more treatment groups to their experimental designs Its best to save your signal intensity data before calculating the FDR, as the FDR calculation will change the signal values for all of your data
A student wants to see if the number of times a book has been checked out of the library in the past year and the number of pages in the book are related. She guesses that the number of times a book has been checked out of the library in the past year will be a predictor of the number of pages it has. She randomly sampled 15 books from the library, test her claim at a 0.05 level of significance. number of times checked out number of pages 13 223 45 350 49 377 30 371 3 343 7 280 17 218 7 265 20 382 23 287 1 313 30 388 20 358 2 311 40 421 The correlation coefficient: r= (round to 3 decimal places) The equation y=a+bx is: (round to 3 decimal places) y=+ x The hypotheses are: H0:ρ=0H0:ρ=0 (no linear relationship)HA:ρ≠0HA:ρ≠0 (linear relationship) (claim) Since αα is 0.05 the critical value is -2.16 and 2.16 The test value is: (round to 3 decimal places) The p-value is: (round to 3 decimal places) The decision is to reject H0H0 do not reject…
One study claimed that 91%91% of college students identify themselves as procrastinators. A professor believes that the claim regarding college students is too high. The professor conducts a simple random sample of 118118 college students and finds that 102102 of them identify themselves as procrastinators. Does this evidence support the professor’s claim that fewer than 91%91% of college students are procrastinators? Use a 0.010.01 level of significance.Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places
US Universities found that 72% of people are concerned about the possibility that their personal records could be stolen over the internet. If a random sample of 300 college students at a Midwestern university were taken and 228 of them were concerned about the possibility that their personal records could be stolen over the Internet, could you conclude at the 0.025 level of significance that a higher proportion of the university’s college students are concerned about Internet theft than the public at large? Report the p-value for this test. Z0.025 = 1.96
A random sample of857births included434boys. Use a 0.01significance level to test the claim that 51.4% of newborn babies are boys. Do the results support the belief that 51.4% of newborn babies are boys?
Q.No.5. a) why confounding is used in experiment b) Construct factorial design with BCD confounded in first replicate, ABD confounded in second replicate and AD confounded in third. Outline the analysis of variance.
Researchers selected a simple random sample of 4048 medical records of adults diagnosed with gum disease. In all, 2226 were current smokers, 891 were former smokers, and 931 never smoked regularly. Their research question is: Do these data indicate that gum disease is equally likely regardless of smoking status? What is the chi-square statistic for the null hypothesis of an equal representation of current, former, and never smokers among adults diagnosed with gum disease? 854.95 1349.33 4048 O 1/3
A publisher reports that79%of their readers own a personal computer. A marketing executivewants to test the claim that the percentage is actually more than the reported percentage. A randomsample of 100 found that89%of the readers owned a personal computer. Is there sufficient evidence atthe 0.02 level to support the executive’s claim?
In a study of red/green color blindness, 800 men and 2050 women are randomly selected and tested. Among the men, 68 have red/green color blindness. Among the women, 5 have red/green color blindness. We wish to test the claim that men have a higher rate of red/green color blindness. The test statistic is?The p-value is?
10
Female undergraduates in randomized groups of 15 took part in a self-esteem study. The study measured an index of self-esteem from the point of view of competence, social acceptance, and physical attractiveness. Let x1, x2, and x3 be random variables representing the measure of self-esteem through x1 (competence), x2 (social acceptance), and x3 (attractiveness). Higher index values mean a more positive influence on self- esteem. Variable Sample Mean Standard Deviation Population Size Мean 15 19.48 2.92 X1 X2 X3 (a) Find a 90% confidence interval for u1 - 42. (Round your answers to two decimal places.) lower limit 15 19.90 3.98 H2 15 17.42 3.60 upper limit (b) Find a 90% confidence interval for u1 - 43. (Round your answers to two decimal places.) lower limit upper limit (c) Find a 90% confidence interval for u2 - 13. (Round your answers to two decimal places.) lower limit upper limit
ANOVA is used for comparing across 3 or more groups.In ANOVA, the null hypothesis is always: at least one variance is different. at least one mean is different. all means are equal. all variances are equal

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