A student can either take the exam though Computer Based Testing (CBT) or Paper and Pencil Testing (PPT). I take a sample of 5 students who took the exam through CBT and another sample of 5 students who took the exam through PPT and obtained their scores out of 100. Is there sufficient evidence to conclude that the students who took the exam through CBT have a higher average score compared to the students who took the exam through PPT? Test at α = 0.03. CBT Scores PPT Scores 82 67 78 74 93 68 83 76 76 74

A student can either take the exam though Computer Based Testing (CBT) or Paper and Pencil Testing (PPT). I take a sample of 5 students who took the exam through CBT and another sample of 5 students who took the exam through PPT and obtained their scores out of 100. Is there sufficient evidence to conclude that the students who took the exam through CBT have a higher average score compared to the students who took the exam through PPT? Test at α = 0.03. CBT Scores PPT Scores 82 67 78 74 93 68 83 76 76 74

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Description: 3. A student can either take the exam though Computer Based Testing (CBT) or Paper and Pencil Testing (PPT). I takea sample of 5 students who took the exam through CBT and another sample of 5 students who took the examthrough PPT and obtained their

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Twenty middle-aged men with glucose readings between 90 milligrams per deciliter and 120 milligrams per deciliter of blood were selected randomly from the population of similar male patients at a large local hospital. Ten of the 20 men were assigned randomly to group A and received a placebo. The other 10 men were assigned to group B and received a new glucose drug. After two months, posttreatment glucose readings were taken for all 20 men and were compared with pretreatment readings. The reduction in glucose level (Pretreatment reading − Posttreatment reading) for each man in the study is shown here. Group A (placebo) reduction (in milligrams per deciliter): 12, 8, 17, 7, 20, 2, 5, 9, 12, 6 Group B (glucose drug) reduction (in milligrams per deciliter): 29, 31, 13, 19, 21, 5, 24, 12, 8, 21 Part A: Do the data provide convincing evidence, at the α = 0.02 level, that the glucose drug is effective in producing a reduction in mean glucose level? Part B: Create and interpret a 98%…
A researcher is testing the effectiveness of an intervention for patients with type 2 diabetes and depression that focuses on increasing medication adherence compared with usual primary care. Patients randomized to the intervention group were more likely to achieve remission of depression compared with patients in the usual care group at 12 weeks (intervention 58.7% vs usual care 30.7%, p < .001). Based on this information and the information found in table 1, how would you interpret the study findings. Table 1. Baseline Characteristics of Study Population Characteristic Sociodemographic Age, mean (SD) y African American, n (%) White, n (%) Hispanic, n (%) Other, n (%) Years with diabetes, mean (SD) MMSE score, mean (SD) Usual Care (n=88) 57.1 (9.6) 48 (54.5) 36 (40.9) 3 (3.4) 1 (1.1) 12.0 (11.8) 28.2 (2.3) Intervention (n=92) 57.8 (9.4) 54 (58.7) 29 (31.5) 4 (4.3) 5 (5.4) 10.5 (1.2) 28.2 (2:3) P value .63 .30 .02 ,99 4 TRA 1
A pharmaceutical company has developed a new drug called Antisubcillin to treat substance use disorder. They have just completed an experiment assessing the safety of the drug. To test safety, 100 rats were given 20 mg of Antisubcillin and 100 rats were given a placebo. The study was conducted as a double-blind controlled study and so the researchers did not know which rats were receiving the drug and which were receiving the placebo. The number of negative side effects displayed by each rat over the course of 8 weeks was recorded. Which statistical test should be used to analyze these data? z test one-sample t test independent samples t test dependent samples t test
I am testing whether a new group study technique improves PSYC 214 students’ final exam grades. In this situation, what would be a Type I error? What would be a Type II error?
A study of parental empathy for sensitivity cues and baby temperament (higher scores mean more empathy) was performed. Let x, be a random variable that represents the score of a mother on an empathy test (as regards her baby). Let x, be the empathy = 68.36. Another random sample of 31 fathers gave score of a father. A random sample of 37 mothers gave a sample mean of x, X, = 60.06. Assume that o, = 11.55 and o, = 11.45. (a) Let u, be the population mean of x, and let u, be the population mean of x,. Find a 99% confidence interval for u, - Hz. (Round your answers to two decimal places.) lower limit upper limit (b) Examine the confidence interval and explain what it means in the context of this problem. Does the confidence interval contain all positive, all negative, or both positive and negative numbers? What does this tell you about the relationship between average empathy scores for mothers compared with those for fathers at the 99% confidence level? Because the interval contains only…
Prior to an intensive TV advertising campaign, the producers of Nike athletic shoes find that 29 of a random sample of 200 upper-income adults are aware of their new leisure shoe line. A second random sample of 300 such adults is taken after the campaign. Now 96 of the persons sampled can identify the new line. Is the increase in the proportion of upper income adults showing brand awareness significant? Test the claim using alpha = .05.
A pharmaceutical company has developed a drug that is expected to reduce hunger. To test the drug, three samples of rats are selected with n = 11 in each sample. The first sample receives the drug every day. The second sample is given the drug ance a week, and the third sample receives no drug at all (the control group). The dependent variables is the amount of food eaten by each rat aver a 1-month period. These data are analyzed by an ANOVA, and the results are reported in the following summary Lable. Fill in all missing values in the Lable. (Hint: Start with the df column.) s.S. d.f. M.S. IF Between 6.57 Within 4.35 TOTAL Use the =FDIST () function in Excel to locate the p-value for this ANOVA: pvalue- Report answer accurate to at least 4 decimal places. If you use a signilficance level of a = 05, what would you condlude about these treatments? OThese data do not pravide evidence of a difference between Lhe treatments OThere is a significant difference between treatments
Psychiatrists believe that learning through physical guidance will improve self-care skills. For 4 months the psychiatrists worked with mentally impaired individuals in which half were taught self-care skills through video imitation and the other half through physical guidance. At the end of the 4 months, individuals were asked to independently perform the self-care task and were rated on the level of required assistance where a higher score indicates more assistance. What can be concluded with an α of 0.05? The rating data are below. video imitation physical guidance 10 15 10 13 17 16 11 17 11 19 14 21 11 16 14 14 16 20 A)Obtain/compute the appropriate values to make a decision about H0. Critical Value= Test Statistic= B)Compute the corresponding effect size(s) and indicate magnitude(s). d= r2= C)If appropriate, compute the CI. If not appropriate, input "na" for both spaces below.
When only two treatments are involved, ANOVA and the Student’s t-test (Chapter 11) result in the same conclusions. Also, for computed test statistics, t2 = F. To demonstrate this relationship, use the following example. Fourteen randomly selected students enrolled in a history course were divided into two groups, one consisting of six students who took the course in the normal lecture format. The other group of eight students took the course in a distance format. At the end of the course, each group was examined with a 50-item test. The following is a list of the number correct for each of the two groups. Traditional Lecture Distance 36 45 31 35 40 45 34 35 33 45 38 36 43 41 a-1. Complete the ANOVA table. (Round your SS, MS, and F values to 2 decimal places and p-value, F crit to 4 decimal places.) Source of Variation SS df MS F p-value F crit Treatment 96.01 1 96.01 5.67 0.0350 Error 203.21 12 16.93 Total 299.21 13…
Photon is a training device that is designed to improve a user's reaction time. Similar devices have been criticized for being too easy to master, but the makers of Photon say that their device is built to give most users room to improve. The makers say that even among professional athletes, the proportion, , who can score the top ranking of "light speed" is less than 16%. A random sample of 110 professional athletes is chosen, and 14 score a ranking of "light speed" while using the device.Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the level of significance, to support the claim that the proportion of all professional athletes who can score a ranking of "light speed" is less than 16% .
A study was made of 413 children who were hospitalized as a result of motor vehicle crashes. Among 290 children who were not using seat belts, 60 were injured severely. Among 123 children using seat belts, 16 were injured severely (based on data from "Morbidity Among Pediatric Motor Vehicle Crash Victims: The Effectiveness of Seat Belts," by Osberg and Di Scala, American Journal of Public Health, Vol. 82, No. 3). For this problem we want to know, is there sufficient sample evidence to conclude, at the 0.05 significance level, that the proportion of severe injuries is higher for children not wearing seat belts? Let pi be the proportion of severe injuries among all children not wearing seatbelts and who were involved in crashes. Let p2 be the proportion of severe injuries among all children wearing seatbelts and who were involved in crashes. Which is the proper expression of Ho? Pi = P2 O Pi P2 Which is the proper expression of H1? O pi P2 Calculate p1 to 4 decimal places: Calculate p,…
A randomized controlled trial was conducted to determine whether treatment with daily aspirin was more effective than placebo at preventing myocardial infarction (MI) (within 5 years). A total of 140 out of 11,140 subjects in the aspirin group experienced an MI, while 240 out of 11,040 subjects in the placebo group experienced an MI. The relative risk of MI comparing aspirin to placebo was calculated to be 0.58, and its 95% confidence interval ranged from 0.47 to 0.71. Which of the following can be concluded from these results? Question 4 options: On average, the risk of MI among subjects who used aspirin was 0.58 times the risk of MI among those on placebo. On average, aspirin reduced the risk of MI in this population by 58% when compared to placebo. Aspirin is almost certainly harmful to this population. Compared to placebo, aspirin did not reduce the risk of MI by a statistically significant amount.