A pharmaceutical company has developed a drug that is expected to reduce hunger. To test the drug, three samples of rats are selected with \(n = 11\) in each sample. The first sample receives the drug every day. The second sample is given the drug once a week, and the third sample receives no drug at all (the control group). The dependent variable is the amount of food eaten by each rat over a 1-month period. These data are analyzed by an ANOVA, and the results are reported in the following summary table. Fill in all missing values in the table. (Hint: Start with the \(df\) column.)| | SS | df | MS | F ||------------------|------|-----|-----|------|| Between | | | | 6.57 || Within | | | 4.35 | || TOTAL | | | | |Use the **FDIST()** function in Excel to locate the p-value for this ANOVA:p-value = ___________Report answer accurate to at least 4 decimal places.If you use a significance level of \(\alpha = .05\), what would you conclude about these treatments?- These data do not provide evidence of a difference between the treatments- There is a significant difference between treatments

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Description: A pharmaceutical company has developed a drug that is expected to reduce hunger. To test the drug, three samples of rats are selected with \(n = 11\) in each sample. The first sample receives the drug every day. The second sample is given the drug o

Given that : A pharmaceutical company has developed a drug that is expected to reduce hunger. To test the drug, three samples are selected with n = 11 in each sample. Let k denote the number of samples taken i.e. k =3 Let N denote the total sample size i.e n = 11 for each then N = 33 for three samples. The ANOVA formulae table is given below : Steps to calculate table values We know that k = 3 and N = 3 therefore we get all d.f values Now F- value = MSG/MSE = 6.57 annd MSE = SSE/DFE= 4.58. Therefore, MSG = MSE*F Therefore, MSG = 30.09 Now, MSG = SSG/DFG where DFG = 2 Therefore, SSG = 15.45 Similarly, MSE = SSE/DFE, where DFE = 30 Therefore, SSE = 137.5 Hence, the table values is : where p - value is using excel command : F.DIST(x, deg_freedom1, deg_freedom2, cumulative) where x = 6.57, deg_freedom1 = 2, deg_freedom2 = 30, cumulative = FALSE Therefore, p - value = 0.0029 Decision rule - If p -value < 0.05. Reject Ho. If p -value > 0.05 then do not reject Ho Since p -value < 0.05 therefore, Reject Ho. Hence, There is significance difference between the treatments.

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A pharmaceutical company has developed a drug that is expected to reduce hunger. To test the drug, three samples of rats are selected with n = 11 in each sample. The first sample receives the drug every day. The second sample is given the drug ance a week, and the third sample receives no drug at all (the control group). The dependent variables is the amount of food eaten by each rat aver a 1-month period. These data are analyzed by an ANOVA, and the results are reported in the following summary table. Filin all missing values in the Lable. (Hint: Start with the df column.) s.S. d.f. M.S. Between 6.57 Within 4.35 TOTAL Use the =FDIST() function in Excel to locate the pvalue for this ANOVA: value- Report answer accurate to at least 4 decimal places. If you use a signilficance level of a = 0S, what would you conclude about these treatments? OThese data do no pravide evidence of a difference between the treatments OThere is a signilficant difference between treatments

A pharmaceutical company has developed a drug that is expected to reduce hunger. To test the drug, three samples of rats are selected with n = 11 in each sample. The first sample receives the drug every day. The second sample is given the drug ance a week, and the third sample receives no drug at all (the control group). The dependent variables is the amount of food eaten by each rat aver a 1-month period. These data are analyzed by an ANOVA, and the results are reported in the following summary table. Filin all missing values in the Lable. (Hint: Start with the df column.) s.S. d.f. M.S. Between 6.57 Within 4.35 TOTAL Use the =FDIST() function in Excel to locate the pvalue for this ANOVA: value- Report answer accurate to at least 4 decimal places. If you use a signilficance level of a = 0S, what would you conclude about these treatments? OThese data do no pravide evidence of a difference between the treatments OThere is a signilficant difference between treatments

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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