A spectroscopic binary that has a period of 3.89 days has a near perfect circular orbit. The amplitudes of the velocity curves are 107 km·s−1 and 120 km·s−1. Making appropriate assumptions, estimate the individual masses.
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A spectroscopic binary that has a period of 3.89 days has a near perfect circular orbit. The amplitudes of the velocity curves are 107 km·s−1 and 120 km·s−1. Making appropriate assumptions, estimate the individual masses.
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- A star near the visible edge of a galaxy travels in a uniform circular orbit. It is 48,300 ly (light-years) from the galactic center and has a speed of 275 km/s. Estimate the total mass of the galaxy based on the motion of the star. Gravitational constant is 6.674×10−11 m3/(kg·s2) and mass of the Sun Ms=1.99 × 1030 kg. dont provide hand written solutionTwo identical stars with mass M orbit around their center of mass. Each orbit is circular and has radius R, so that the two stars are always on opposite sides of the circle. Part A Find the gravitational force of one star on the other. Express your answer in terms of G, M, R. Πν ΑΣφ ? F = Part B Find the orbital speed of each star. Express your answer in terms of G, M, R. να ΑΣΦ7 ? Part CPlaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is V = 240 km/s and the orbital period of each is 12.1 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 x 1030 kg.) solar masses XCM M
- Designing an interplanetary mission from Earth to Jupiter. Given the position and velocityvectors for the Earth parking orbit, r = 8228 I +389 J +6888 K (km)v = -0.7 I +6.6 J -0.6 K (km/s) 1.) Assuming that the satellite will enter the Hohmann transfer elliptical orbit from perigee of its current Earth parking orbit, determine the total velocity increment, Δvtotal required for a Hohmann transfer from the Earthparking orbit to 200km altitude Jupiter parking orbit. 2.) Calculate the semi-major axis, period in earth years, and eccentricity of the Hohmann transfer ellipse.Please don't provide handwritten solution .....Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is v| = 225 km/s and the orbital period of each is 11.6 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 x 1030 kg.) M XCM M Part 1 of 3 - Conceptualize From the given data, it is difficult to estimate a reasonable answer to this problem without working through the details and actually solving it. A reasonable guess might be that each star has a mass equal to or slightly larger than our Sun because fourteen days is short compared to the periods of all the Sun's planets. Part 2 of 3 - Categorize The only force acting on each star is the central gravitational force of attraction which results in a centripetal acceleration. When we solve Newton's second law, we can find the unknown mass in terms of the variables…
- Black holes are difficult to observewith telescopes because they, bydefinition, don’t emit or reflect any light. They can be found by look-ing for other nearby objects orbit-ing them, however. Here is a dia-gram of a star in a circular orbit around a black hole. a. The period of the star’s orbit is 90 days, and its orbital radius around the black hole isobserved to be 3.6 : ×10^11 m. Find the orbital velocity of the star in units of m/s. (You need to convert 90 days to seconds, first). The circumference of a circle is 2πr. b. The mass of the star is known to be 4 × 10^30 kg. Find the centripetal acceleration of thestar and the strength of the gravitational force on the star. c. Find the mass of the black hole.D Gm₁m₂ Fg KE = mv², Ug = - 2πr , ac = =²₁, v = ²7₁ T Gm₁m₂ GM g = G, Vesc = 2GM R , E = KE + Ug, G = 6.674 x 10-¹1 Nm²/kg² Problem 1: You are the science officer on a visit to a distant solar system. Prior to landing on a planet you measure its radius to be 9 x 106 m and its rotation period to be 22.3 hours. You have previously determined that the planet orbits 2.2 x 10¹¹ m from its star with a period of 402 days (3.473 x 107 sec). Once on the surface you find that the free-fall acceleration is 12.2 m/sec². a) What is the mass of the planet? Answer: 1.5 x 1025 kg. b) What is the mass of the star? Answer: 5.2 x 1030 kg.A massive black hole is believed to exist at the center of our galaxy (and most other spiral galaxies). Since the 1990s, astronomers have been tracking the motions of several dozen stars in rapid motion around the center. Their motions give a clue to the size of this black hole. (a) One of these stars is believed to be in an approximātely circular orbit with a radius of about 1.50 x 10° AU and a period of approximately 30 yr. Use these numbers to determine the mass of the black hole around which this star is orbiting. kg (b) What is the speed of this star? V star m/s How does it compare with the speed of the Earth in its orbit? V star VEarth How does it compare with the speed of light? V star
- Please solveAn astronomer is measuring the light emitted by a binary star system. One of the stars appears to be much more massive than the other. The astronomer notices that the smaller star orbits the larger one in a nearly circular orbit at fr = 845 ×10º| a distance of r = 845 x 106 km. Through careful observation, she measures the smaller star's orbital speed to be v 12.0 km/s. Using Keppler's Laws she calculates the mass of the larger star. What is it? Use G = 6.67 x 10-¹1 N-m²/kg². - M = 30 x1030 kg (± 0.05 × 10³0 kg)Plaskett's binary system consists of two stars that revolve in a circular orbit about a center of mass midway between them. This statement implies that the masses of the two stars are equal (see figure below). Assume the orbital speed of each star is V = 210 km/s and the orbital period of each is 11.5 days. Find the mass M of each star. (For comparison, the mass of our Sun is 1.99 x 1030 kg.) solar masses M XCM M