A particle of mass m is placed at a distance r away from the center of a thin circular hoop of mass M and radius R. The particle is in the plane of the hoop, and r < R. M. Find the gravitational force on the particle. Does your answer make sense in the limit r + 0? r + R? 2.
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![A particle of mass m is placed at a distance r away from the center of a thin
circular hoop of mass M and radius R. The particle is in the plane of the hoop, and r < R.
M.
Find the gravitational force on the particle. Does your answer make sense in the limit r + 0?
r + R?
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- Can I please get some help with the key concepts and principles, please and thank you!A satellite in geostationary orbit (also called synchronous orbit) appears to remain stationary in the sky as seen from any particular location on the planet. a.) In the future, there will be need for satellites in synchronous orbit around Mars to aid colonies. At what altitude would such a satellite need to be above the surface of Mars?Assume that the mass of Mars is 6.39 × 10^23 kg, the length of the Martian solar day (i.e., sol) is 24h 39m 35s, the length of the sidereal day is 24h 37m 22s, and the equatorial radius is 3396 km. (Hint: if you haven’t had a physics class before, you can find this by using the fact that the acceleration of an object in circular motion either as v2/r, where v and r are the velocity and radius of the orbit, or as 4Pi 2r/T2 , where T is the period. Use this second equation and Mathematical Insight 4.5 on p. 131 to find r for T=1 day. Make sure to use values for Mars nstead of Earth, as necessary. Alternatively, you can calculate the answer using Newton’s…Chapter 04, Problem 029 2 Your answer is partially correct. Try again. The drawing shows three particles far away from any other objects and located on a straight line. The masses of these particles are to the right. Find the net gravitational force, including sign, acting on (a) particle A, (b) particle B, and (c) particle C. ma = 322 kg, mp = 589 kg, and m. = 185 kg. Take the positive direction to be 0.500 m 0.250 m (a) Number 0.00005796 UnitsTN (b) NumberTo.00006568 Units (c) Number12.335 Units
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