we added a 30 mg (that's 30 x 10-6 kg) mass to the upper wire and the laser spot on the scale dropped down from 24.2 cm at equilibrium to 22.9 cm with the mass on it. That change on the scale of 1.3 cm represents the effect of the gravitational force due to the weight of 30 mg. This calibrates the response of the balance to forces. What is the scale factor "b" such that FB = b y where FB is in micro-newtons (10-6 N) and y is the spot deflection on the scale in centimeters? Pick the answer closest to what you calculate using the scale readings 24.2 (equilibrium) and 22.9 (30 mg). 23.1 226 0.209 0.000226

we added a 30 mg (that's 30 x 10-6 kg) mass to the upper wire and the laser spot on the scale dropped down from 24.2 cm at equilibrium to 22.9 cm with the mass on it. That change on the scale of 1.3 cm represents the effect of the gravitational force due to the weight of 30 mg. This calibrates the response of the balance to forces. What is the scale factor "b" such that FB = b y where FB is in micro-newtons (10-6 N) and y is the spot deflection on the scale in centimeters? Pick the answer closest to what you calculate using the scale readings 24.2 (equilibrium) and 22.9 (30 mg). 23.1 226 0.209 0.000226

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Question

we added a 30 mg (that's 30 x 10^-6 kg) mass to the upper wire and the laser spot on the scale dropped down from 24.2 cm at equilibrium to 22.9 cm with the mass on it. That change on the scale of 1.3 cm represents the effect of the gravitational force due to the weight of 30 mg. This calibrates the response of the balance to forces. What is the scale factor "b" such that

F_B = b y

where F_B is in micro-newtons (10^-⁶ N) and y is the spot deflection on the scale in centimeters?

Pick the answer closest to what you calculate using the scale readings 24.2 (equilibrium) and 22.9 (30 mg).