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Consider Kepler's equation regarding planetary orbits, given as
M = E e sin(E),
π
where M is the mean anomaly, E is the eccentric anomaly, and e measures eccentricity. Find the eccentric anomaly E when
7
and the eccentricity of the orbit e = 0.37. Use Newton's method with initial approximation
Xo = 2 to find x2, rounded to the nearest thousandth.
the mean anomaly M =
Provide your answer below:
Xx₂≈

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