A specific single nucleotide variation in the human genome occurs with -2.5% frequency in the general population. This variation occurs within the protein coding region and results in an alanine where glycine is commonly found. This variant can best be described as a: Missense mutation Nonsynonymous coding single nucleotide polymorphism Non-coding single nucleotide polymorphism Synonymous coding single nucleotide polymorphism Sense mutation
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- A wildtype gene produces the polypeptide sequence: Wildtype: Met-Ser-Pro-Arg-Leu-Glu-Gly Each of the following polypeptide sequences is the result of a single mutation. Identify the most likely type of mutation causing each, be as specific as possible. M1:Met-Ser-Ser-Arg-Leu-Glu-Gly missense mutation M2:Met-Ser-Pro M3:Met-Ser-Pro-Asp-Trp-Arg-Asp-Lys M4:Met-Ser-Pro-Glu-Gly nonsense mutation frameshift insertion in frame deletion M5:Met-Ser-Pro-Arg-Leu-Glu-Gly in frame insertionA polypeptide has the following amino acid sequence: Met-Ser-Pro-Arg-Leu-Glu-Gly The amino acid sequence of this polypeptide was determined in a series of mutants listed in parts a through e. indicate the type of mutation that occurred in the DNA (single-base substitution, insertion, deletion) and the phenotypic effect of the mutation (nonsense mutation, missense mutation, frameshift, etc.). a. MMutant 4: Met-Ser-Pro-Glu-GlWhen considering the mutational options for a nucleotide such as thymine, there is a single transition and two transversion type mutations that are possible, which is why we observe transversions to occur more frequently in nature when genomes are examined. O True O False
- The following is a list of mutational changes. For eachof the specific mutations described, indicate which ofthe terms in the right-hand column applies, either as adescription of the mutation or as a possible cause.More than one term from the right column can applyto each statement in the left column.1. an A–T base pair in the wild-type gene ischanged to a G–C pair2. an A–T base pair is changed to a T–A pair3. the sequence AAGCTTATCG is changed toAAGCTATCG4. the sequence CAGCAGCAGCAGCAGCAGis changed toCAGCAGCAGCAGCAGCAGCAGCAG5. the sequence AACGTTATCG is changed toAATGTTATCG6. the sequence AACGTCACACACACATCGis changed to AACGTCACATCG7. the sequence AAGCTTATCG is changed toAAGCTTTATCGa. transitionb. basesubstitutionc. transversiond. deletione. insertionf. deaminationg. X-rayirradiationh. intercalatori. slippedmispairingA double mutant produced by uneven crossing-over contains two single nucleotide mutations that result in frame shifts and are separated by about 20 base pairs. The first is an insertion, while the second is a deletion. The amino acid sequences of the wildtype and mutant polypeptide in this region of the protein are as follows: Wildtype: Lys – Lys – Tyr – His – Gln – Trp – Thr – Cys – AsnDouble Mutant: Lys – Gln – Ile – Pro – Pro – Val – Asp – Met – Asn a) What are the original and double mutant mRNA sequences. You may find it useful to use the conventional symbols Y for pyrimidine, R for purine, N for any nucleotide, and H for A,C, or T. 2. b) Which nucleotide was inserted? 3. c) Which nucleotide was deleted?You learned in Problem 21 in Chapter 7 that theneurodegenerative disease ALS can be caused by expansion of a hexanucleotide repeat region (5′-GGGGCC-3′)outside of the open reading frame (but within the firstintron) of the gene called C9ORF72. While a normalC9ORF72 allele has 2–23 copies of the hexanucleotiderepeat unit, dominant disease-causing alleles have hundreds or even thousands of copies. Researchers observed that the first intron of theC9ORF72 disease allele is transcribed not only fromthe normal template strand of DNA, but also from thenontemplate strand. Even more unusual, both types ofrepeat-region transcripts are translated in all six readingframes in an AUG-independent manner—a processcalled repeat-associated non-ATG translation, or RANtranslation. These discoveries led to the hypothesisthat the proteins made from the repeats mightcontribute to ALS.a. What polypeptides are made from the repeat-regiontranscripts?b. According to the RAN translation hypothesis, whyare…
- Two types of mutations discussed in this chapter are (1) nucleotide changes and (2) unstable genome regions that undergo dynamic changes. Describe each type of mutation.G-LO37 Identify the consequences of mutations in different regions of a gene. The image below represents two strands of DNA: the top one corresponds to a healthy individual, and the bottom one of a sibling potentially affected with a disease due to genetic mutations Mutation 1 A + с AUA ACA AUG Met ACG GUU GUC GUA GUG Val GCU GCC GCA GCG It will result in mRNA produced Mutation 2 It will result in no mRNA produced 500 AGG The protein produced will be normal 500 + GGG Ala The Select all that applies about Mutation 1 (position -6): AAGLys AGA Arg GGU GGC GGA GGG GAC Asp GAA Glu GAGJ Gly The protein produced will have a different amino acid 1235 ATT 1235 TTT 070 2070 ALL The mutation occurs in the promoter region, and this means that the mRNA cannot be produced 1535 The mRNA and protein will both be normal because the mutation occurs outside of the consensus region of the promoter G 1535 с AffectedA nonsynonymous mutation is also referred to as missense mutation. Which of the following correctly describe these mutations? They are permanent and cannot revert or reverse mutate back into a wild-type sequence. They cause a non-functional amino acid to replace a functional amino acid. O They result in the insertion or deletion of a small number of nucleotides to the DNA. They change the nucleotide sequence of a gene but do not change the sequence of the resulting protein. None of the provided answers are correct. They convert a codon for a particular amino acid within a gene into a stop codon. They insert an additional amino acid into the final protein product.
- A 210-bp sequence within the CFTR gene on human chromosome 7 is shown below. The three bold underlined nucleotides are deleted in a common cystic fibrosis (CF) mutation, removing a phenylalanine amino acid from the CFTR protein. 1 AGAGGGTAAA ATTAAGCACA GTGGAAGAAT TTCATTCTGT TCTCAGTTTT 51 CCTGGATTAT GCCTGGCACC ATTAAAGAAA ATATCATCTT TGGTGTTTCC 101 TATGATGAAT ATAGATACAG AAGCGTCATC AAAGCATGCC AACTAGAAGA 151 GGTAAGAAAC TATGTGAAAA CTTTTTGATT ATGCATATGA ACCCTTCACA 201 CTACCCAAAT PCR primers have been designed to amplify fragments within this sequence: Forward: GGATTATGCCTGGCACCATT Reverse: AGTGTGAAGGGTTCATATGC DNA from a CF patient is tested with a PCR assay using a pair of these primers, and the PCR product is found to be 3 bp shorter than that expected from the sequence shown above. What length PCR products (in bp) would you expect in the mother of the CF patient? A. 95 and 92 B. 149 C. 133 and 130 D. 149 and 146 E. 146The table shows the partial sequences of a wild type polypeptide and three mutant polypeptides as well as the type of single nucleotide mutation that produced each mutant polypeptide. Peptide sequence Met - Leu - Arg - Ile - ... Type of mutation Wild type Met - Leu - Arg - Met - ... Met - Leu - [STOP] Mutant 1 transition Mutant 2 transversion Mutant 3 Met - Phe - Arg - Ile - ... transition Determine the mRNA sequence for the wild type polypeptide by identifying the codons that correspond to each amino acid. The first codon has been filled in for you. Codon information can be found in the codon access table. Met Leu Arg Ile Answer Bank CỦA AUA CGU CGA AUG AUC AGA UUG CÚCDescribe the mutation that occurs in the following examples (be specific, if possible): BOAT to BAT SOAP to SOUP PAY to PLAY GCTCT to GCACT TGCCC to TACCC CATGC to GATGC TATATA to TACATA