A source of AC emf E₁ = 120/30º volts with an impedance of Z₁ = 2/0° ohms is connected in parallel with another AC source of E2 = 120/-300 volts with an impedance Z₂ = 2/90° ohms. The two AC source are use to supply a load impedance of Z₁ = 10/-53.10 ohms. Calculate the value of the load current IL. О а. O a. 7.62 amperes O b. 4.42 amperes O c. 5.38 amperes O d. 6.48 amperes

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
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A source of AC emf E₁ = 120/300 volts with
an impedance of Z₁ = 2/0° ohms is
connected in parallel with another AC
source of E₂ = 120/-30º volts with an
impedance Z₂ = 2/90° ohms. The two AC
source are use to supply a load impedance
of Z₁ = 10/-53.10 ohms. Calculate the value
of the load current IL.
O a. 7.62 amperes
O b. 4.42 amperes
O C.
5.38 amperes
O d. 6.48 amperes
Transcribed Image Text:A source of AC emf E₁ = 120/300 volts with an impedance of Z₁ = 2/0° ohms is connected in parallel with another AC source of E₂ = 120/-30º volts with an impedance Z₂ = 2/90° ohms. The two AC source are use to supply a load impedance of Z₁ = 10/-53.10 ohms. Calculate the value of the load current IL. O a. 7.62 amperes O b. 4.42 amperes O C. 5.38 amperes O d. 6.48 amperes
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