A small signal equivalent circuit of single common-emitter amplifier is shown in Figure Q1.b with quiescent collector current of 5 mA and a total of 1 k. The transistor parameters are ß = 100, r = 200, Rs = 286, C₁ = 2 pF, fr = 200 MHz. 1) Deduce the values of 9m, Cfß. 2) Calculate the low-frequency voltage gain Vo/Vs. 1 [Hint: fr = Bfpi f = 2 (G+Cu) fß: Vs Rs b V be Ib b' ₁₂C₁=C₁= IT Figure Q1.b gmV 2 ro C₂ Cs Rc RL

A small signal equivalent circuit of single common-emitter amplifier is shown in Figure Q1.b with quiescent collector current of 5 mA and a total of 1 k. The transistor parameters are ß = 100, r = 200, Rs = 286, C₁ = 2 pF, fr = 200 MHz. 1) Deduce the values of 9m, Cfß. 2) Calculate the low-frequency voltage gain Vo/Vs. 1 [Hint: fr = Bfpi f = 2 (G+Cu) fß: Vs Rs b V be Ib b' ₁₂C₁=C₁= IT Figure Q1.b gmV 2 ro C₂ Cs Rc RL

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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For the transistor in a circuit shown in Figure 3. B= 90 and Va = 150 V. v*= +5 V I0.5 mA "ao Ca 0.5 k2 V=-5 V Figure 3 (a) Calculate the small-signal parameters gm, Iz, and ro. (b) Draw the small-signal equivalent eircuit. (c) Determine the small-signal voltage gain. ww
VcC R2 RC- RI RL R1 RE VEE Assume: B=100, VA=150, Vcc=12V, VɛE=GND, R=2K, R1=160K, R2=300K, Rɛ=3K, Rc=2.2K, and R1=100K. A.)For the circuit draw the AC equivalent circuit (including the small signal model for the transistor). Then compute r„, ľo, and gm. Then compute Av (the gain for the entire circuit), and Rin (for the whole circuit). B.)Convert the circuit to a common-collector circuit. Draw the new circuit (assume the same values for the input and load resistances). Then compute the terminal voltage gain, and Rin (for the whole circuit), re-computing any parameters that you need to solve.
Elecronics Engineering
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c) Figure 2.3 shows the circuit diagram of a typical npn BJT common emitter amplifier. The values of RB1-30 kOhm, RB2=10.XY kOhm, Rc-3.XY kOhm, Ic=2.XY mA and Vcc=24 V. If the transistor current gain 3 = 50 determine using the full analysis and assuming VBE = 0.7 V the value of RE, hence identify the location of the Q-point (Ic, VCE, IB and VBE). Now sketch the AC circuit model of this amplifier and determine the value of the ac open circuit voltage gain Av and the ac short circuit current gain Ai. (Assume that Vth = 26 mV). Vin RB1 Cin lin RB2 -10 Rc VB RE + Vcc Vc Cout VE www li Figure 2.3 Vout Ce ¡out x=1 y=7
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