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A small signal equivalent circuit of single common-emitter amplifier is shown in Figure Q1.b with quiescent collector current of 5 mA and a total of 1 k. The transistor parameters are = 100, r = 200, Rs = 2860, C₁ = 2 pF, fr = 200 MHz. 1) Deduce the values of 9m, C fß. 2) Calculate the low-frequency voltage gain V/V. 1 [Hint: fr = BfBi ÍB = 2(C+Cu) fB Vs Rs b ľb V be C₂ Cs Rc RL 50G₁=c=1v₂ Dan Doa compa gmVr b' Figure Q1.b

A small signal equivalent circuit of single common-emitter amplifier is shown in Figure Q1.b with quiescent collector current of 5 mA and a total of 1 k. The transistor parameters are = 100, r = 200, Rs = 2860, C₁ = 2 pF, fr = 200 MHz. 1) Deduce the values of 9m, C fß. 2) Calculate the low-frequency voltage gain V/V. 1 [Hint: fr = BfBi ÍB = 2(C+Cu) fB Vs Rs b ľb V be C₂ Cs Rc RL 50G₁=c=1v₂ Dan Doa compa gmVr b' Figure Q1.b

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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A small signal equivalent circuit of single common-emitter amplifier is shown in Figure Q1.b with quiescent collector current of 5 mA and a total of 1 k. The transistor parameters are ß = 100, r = 200, Rs = 286, C₁ = 2 pF, fr = 200 MHz. 1) Deduce the values of 9m, Cfß. 2) Calculate the low-frequency voltage gain Vo/Vs. 1 [Hint: fr = Bfpi f = 2 (G+Cu) fß: Vs Rs b V be Ib b' ₁₂C₁=C₁= IT Figure Q1.b gmV 2 ro C₂ Cs Rc RL
Transcribed Image Text:A small signal equivalent circuit of single common-emitter amplifier is shown in Figure Q1.b with quiescent collector current of 5 mA and a total of 1 k. The transistor parameters are ß = 100, r = 200, Rs = 286, C₁ = 2 pF, fr = 200 MHz. 1) Deduce the values of 9m, Cfß. 2) Calculate the low-frequency voltage gain Vo/Vs. 1 [Hint: fr = Bfpi f = 2 (G+Cu) fß: Vs Rs b V be Ib b' ₁₂C₁=C₁= IT Figure Q1.b gmV 2 ro C₂ Cs Rc RL
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