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3. The parameters of the transistor in Figure 3 are ß= 100 and VA 100 V. (a) Find the de voltages at the base and emitter terminals. (b) Find Re such that VCEQ = 3.5 V. (c) Assuming Cc and CE act as short circuits, determine the small-signal voltage gain Av = vo / Vs. (d) Repeat part (c) if a 500 2 source resistor is in series with the v, signal source. V+ = +5 V Rc Figure 3 Rs = 100 2 www V₂ Cc RB = 10 ΚΩ 1 = 0.35 mA O V=-5 V OVO CE

3. The parameters of the transistor in Figure 3 are ß= 100 and VA 100 V. (a) Find the de voltages at the base and emitter terminals. (b) Find Re such that VCEQ = 3.5 V. (c) Assuming Cc and CE act as short circuits, determine the small-signal voltage gain Av = vo / Vs. (d) Repeat part (c) if a 500 2 source resistor is in series with the v, signal source. V+ = +5 V Rc Figure 3 Rs = 100 2 www V₂ Cc RB = 10 ΚΩ 1 = 0.35 mA O V=-5 V OVO CE

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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3. The parameters of the transistor in Figure 3 are ß= 100 and V₁ = 100 V. (a) Find the de voltages at the base and emitter terminals. (b) Find Rc such that VCEQ = 3.5 V. (c) Assuming Cc and CE act as short circuits, determine the small-signal voltage gain A, = vo / Vs. (d) Repeat part (c) if a 500 2 source resistor is in series with the v, signal source. V+ = +5 V Rc Figure 3 Rs = 100 52 www Ch Cc RB = 10 ΚΩ 1= 0.35 mA V=-5 V vo CE
Transcribed Image Text:3. The parameters of the transistor in Figure 3 are ß= 100 and V₁ = 100 V. (a) Find the de voltages at the base and emitter terminals. (b) Find Rc such that VCEQ = 3.5 V. (c) Assuming Cc and CE act as short circuits, determine the small-signal voltage gain A, = vo / Vs. (d) Repeat part (c) if a 500 2 source resistor is in series with the v, signal source. V+ = +5 V Rc Figure 3 Rs = 100 52 www Ch Cc RB = 10 ΚΩ 1= 0.35 mA V=-5 V vo CE
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