2.1) Design a BJT common-emitter amplifier (use the figure A or B in former page!)with a gain of 9. The Q point parameters should be IC = 3 mA and VCE = ŠV.A power supply of 20 V is available. Manufacturers' spec sheets give:min = 100, ht. = 200.Take VBE = 0.7 V.2.2) Analyze the BJT circuit given in figure – 1. Determine the collector currents forDC current gains Boc = 100 and BDc = 200. Calculate the Q point of both cases.Detemine the percentage change in Ic (collector current), Vcz (collector-emittercurrent). Use the below formulas:I-IV-VCE -100) 100d-200) -100) 100 : % IcCE( -200)% IcI(-100)Calculate the DC Load line of circuit.CE( -100)Voc-10"R2=1k2R1=300k10VFigure – 1

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2.1) Design a BJT common-emitter amplifier (use the figure A or B in former page!) with a gain of 9. The Q point parameters should be IC = 3 mA and VCE = 8 V. A power supply of 20 V is available. Manufacturers' spec sheets give: min = 100, hte = 200.Take VBE = 0.7 V.

2.1) Design a BJT common-emitter amplifier (use the figure A or B in former page!) with a gain of 9. The Q point parameters should be IC = 3 mA and VCE = 8 V. A power supply of 20 V is available. Manufacturers' spec sheets give: min = 100, hte = 200.Take VBE = 0.7 V.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

2.1) Design a BJT common-emitter amplifier (use the figure A or B in former page!)
with a gain of 9. The Q point parameters should be IC = 3 mA and VCE = ŠV.
A power supply of 20 V is available. Manufacturers' spec sheets give:
min = 100, ht. = 200.Take VBE = 0.7 V.
2.2) Analyze the BJT circuit given in figure – 1. Determine the collector currents for
DC current gains Boc = 100 and BDc = 200. Calculate the Q point of both cases.
Detemine the percentage change in Ic (collector current), Vcz (collector-emitter
current). Use the below formulas:
I
-I
V
-V
CE -100) 100
d-200) -100) 100 : % Ic
CE( -200)
% Ic
I
(-100)
Calculate the DC Load line of circuit.
CE( -100)
Voc-10"
R2=1k2
R1=300k
10V
Figure – 1

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