A simply supported beam is loaded as shown in the figure. Determine the critical spacing provided the details bellow. f'c- 27.6 MPa fy- 415 MPa fyt - 275 MPa Unit weight of concrete - 23.544 kN/cu.m shear reinforcement - 10 mm main reinforcement - 20 mm h- 600 mm b- 400 mm Cc - 50 mm PIDL) - 52 kN P(LL) - 31 kN W(DL) - 21 kN/m WILL) - 9.5 kN/m Note: 1. Use simplified calculation. 2. Round off to a value divisible by 25 for spacing. 3. Design the shear of the critical section only. P (kn) P (kn) Wo (kN/m) + 2.0m 1.5m 2.5m
A simply supported beam is loaded as shown in the figure. Determine the critical spacing provided the details bellow. f'c- 27.6 MPa fy- 415 MPa fyt - 275 MPa Unit weight of concrete - 23.544 kN/cu.m shear reinforcement - 10 mm main reinforcement - 20 mm h- 600 mm b- 400 mm Cc - 50 mm PIDL) - 52 kN P(LL) - 31 kN W(DL) - 21 kN/m WILL) - 9.5 kN/m Note: 1. Use simplified calculation. 2. Round off to a value divisible by 25 for spacing. 3. Design the shear of the critical section only. P (kn) P (kn) Wo (kN/m) + 2.0m 1.5m 2.5m
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Design of Shear (Assignment)
![A simply supported beam is loaded as shown in the figure. Determine the critical spacing provided the details bellow.
f'c = 27.6 MPa
fy = 415 MPa
fyt = 275 MPa
Unit weight of concrete = 23.544 kN/cu,m
shear reinforcement = 10 mm
main reinforcement = 20 mm
h = 600 mm
b = 400 mm
Cc = 50 mm
P(DL) = 52 kN
P(LL) = 31 kN
W(DL) = 21 kN/m
W(LL) = 9.5 kN/m
Note:
1. Use simplified calculation.
2. Round off to a value divisible by 25 for spacing.
3. Design the shear of the critical section only.
P (kn)
P (kN)
Wo (kN/m)
2.0m
1.5m
2.5m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F82733cf8-1bbf-4698-afb8-b2ee1de032d4%2F5f307f13-8e9d-48c1-accc-a4eb1018a5b2%2Fl5cw5lq_processed.png&w=3840&q=75)
Transcribed Image Text:A simply supported beam is loaded as shown in the figure. Determine the critical spacing provided the details bellow.
f'c = 27.6 MPa
fy = 415 MPa
fyt = 275 MPa
Unit weight of concrete = 23.544 kN/cu,m
shear reinforcement = 10 mm
main reinforcement = 20 mm
h = 600 mm
b = 400 mm
Cc = 50 mm
P(DL) = 52 kN
P(LL) = 31 kN
W(DL) = 21 kN/m
W(LL) = 9.5 kN/m
Note:
1. Use simplified calculation.
2. Round off to a value divisible by 25 for spacing.
3. Design the shear of the critical section only.
P (kn)
P (kN)
Wo (kN/m)
2.0m
1.5m
2.5m
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