situation 2 pls! COMPLETE SOLUTION !*draw FBD * use data given properly Situation 1.A horizontal curve with radius equal to 220 m and intersection angle of 126° is to be realigned by rotatingthe forward tangent through an angle of 22° counter clockwise along the PT. If the azimuths of the back andforward tangents are 220° and 346° respectively, stationing of old PC is 10+721.20.1. Compute the central angle of the new curve.2. Compute the radius of the new curve.What is the stationing of the new PC.3.Situation 2.The perpendicular offset distance from point A on a simple curve to Q on the tangent line is 64 m. If thedistance from the P.C to Q on the tangent is 260 m.4. Compute the radius of the simple curve.5. Compute the length of curve from P.C. to A.6. The chords of a compound curve from PC to PCC and from PCC to PT are 130.60 m and 139.16 m,respectively. Its common tangent makes an angle of 20° and 36°, respectively, with the tangents at PC andPT. Determine the length of the long chord of the compound curve.Situation 3.The offset distance of the simple curve from the P.T. to tangent line passing through P.C. is equal to 120.20m. The stationing of P.C. is at 2+540.26. The simple curve has an angle of intersection of 50°.7. Compute the degree of curve.8. Compute the external distance.9. Compute the length of long chord.

Answered: Image /qna-images/answer/6a44c2b4-90ea-40fc-a500-b0d1536746ca.jpg

Answered: orizontal curve with vard tangent…

orizontal curve with vard tangent througl tangents are 220° a. mpute the central an mpute the radius o t at is the stationing

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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