A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F2 = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-).
A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F2 = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-).
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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please explain how to solve, i am not sure what i am doing wrong
![A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have
magnitudes F₁ = 5 kip, F2 = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A
and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical.
Joint F lies s = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the
method of joints to determine the force in each member of the truss, and indicate whether they are in
tension or compression.
Note: Express tension forces as positive (+) and compression forces as negative (-).
A
га
F₁
F3
B
S
LL
E
h
S
PAB =
117.1240
kip
× 0%
PAF = -102.7165
kip
? × 0%
PBC =
87.0837
kip
? × 0%
PBF =
26.3480
kip
× 0%
PCD =
87.0837
kip
? × 0%
PCF =
-61.610
kip
? × 0%
PDE=
117.1240
kip
? × 0%
PDF =
-26.3480
kip
100%
PEF=
-102.7165
kip
× 0%](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F68cfc78d-9a17-4a18-9125-7ed4df6070d3%2Fa1fe3302-b6e8-4117-8b14-499baa497487%2Fhduquef_processed.png&w=3840&q=75)
Transcribed Image Text:A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have
magnitudes F₁ = 5 kip, F2 = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A
and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical.
Joint F lies s = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the
method of joints to determine the force in each member of the truss, and indicate whether they are in
tension or compression.
Note: Express tension forces as positive (+) and compression forces as negative (-).
A
га
F₁
F3
B
S
LL
E
h
S
PAB =
117.1240
kip
× 0%
PAF = -102.7165
kip
? × 0%
PBC =
87.0837
kip
? × 0%
PBF =
26.3480
kip
× 0%
PCD =
87.0837
kip
? × 0%
PCF =
-61.610
kip
? × 0%
PDE=
117.1240
kip
? × 0%
PDF =
-26.3480
kip
100%
PEF=
-102.7165
kip
× 0%
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