A Pratt truss supports three forces at joints along the bottom edge, as shown in the figure below. The forces have magnitudes F₁ = 0 kN, F₂ = 450 kN, and F3 = 100 kN. The lengths for all horizontal members is s = 9 m and for all vertical members is h = 6 m. The truss is held in equilibrium by a pin at point A and a roller at point I. Use the method of joints to determine the force in members CD, CE, DE, DF, and EF and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). B S D S F S H A C E G F₁ F₂ F3 PCD = 0 kN (က) 100% PCE = 0 kN ? × 0% PDE PDF PEF = = = 0 0 kN ? × 0% 0 kN ? × 0% kN 100% S h

A Pratt truss supports three forces at joints along the bottom edge, as shown in the figure below. The forces have magnitudes F₁ = 0 kN, F₂ = 450 kN, and F3 = 100 kN. The lengths for all horizontal members is s = 9 m and for all vertical members is h = 6 m. The truss is held in equilibrium by a pin at point A and a roller at point I. Use the method of joints to determine the force in members CD, CE, DE, DF, and EF and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). B S D S F S H A C E G F₁ F₂ F3 PCD = 0 kN (က) 100% PCE = 0 kN ? × 0% PDE PDF PEF = = = 0 0 kN ? × 0% 0 kN ? × 0% kN 100% S h

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Buckling of columns

The column is described as a vertical member of the structure that carries an axial compressive load, and buckling is a lateral deformation of the column under the application of load.

Question

please help solve, I am not sure what I am doing wrong

A Pratt truss supports three forces at joints along the bottom edge, as shown in the figure below. The forces
have magnitudes F₁ = 0 kN, F₂ = 450 kN, and F3 = 100 kN. The lengths for all horizontal members is
s = 9 m and for all vertical members is h = 6 m. The truss is held in equilibrium by a pin at point A and a
roller at point I. Use the method of joints to determine the force in members CD, CE, DE, DF, and EF and
indicate whether they are in tension or compression.
Note: Express tension forces as positive (+) and compression forces as negative (-).
B
S
D
S
F
S
H
A
C
E
G
F₁
பட்
F₂
F3
PCD =
0
kN
100%
PCE =
0
kN
? × 0%
PDE =
0
kN
? × 0%
PDF
PEF
=
=
0
0
kN
? × 0%
kN
100%
S
h

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Step 1: Draw the free body diagram of the given truss and calculate the reaction at A

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Step 2: Calculate the force in member CE, DE, and DF

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Step 3: Calculate the force in member CD and EF

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