A cantilever truss supports three forces at joints along the top edge, as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F₂ = 6 kip, and F3 = 10 kip. The truss is held in equilibrium by a pin at point A and a roller at point G. The lengths for members DE, EF, and FG is s = 9 ft and for member AG is h = 15 ft. Note that members BF and CE are vertical, and side ABCD is a straight line. The truss members are fabricated from low-carbon steel with a yield strength of S₁ = ±46 ksi. Using the method of sections, determine the minimum cross sectional areas for members AB, BF, and EF so that each one exhibits a safety factor of SF 3.9 with respect to yielding. Note: Express tension forces as positive (+) and compression forces as negative (-). A F₁₂ B F₂
A cantilever truss supports three forces at joints along the top edge, as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F₂ = 6 kip, and F3 = 10 kip. The truss is held in equilibrium by a pin at point A and a roller at point G. The lengths for members DE, EF, and FG is s = 9 ft and for member AG is h = 15 ft. Note that members BF and CE are vertical, and side ABCD is a straight line. The truss members are fabricated from low-carbon steel with a yield strength of S₁ = ±46 ksi. Using the method of sections, determine the minimum cross sectional areas for members AB, BF, and EF so that each one exhibits a safety factor of SF 3.9 with respect to yielding. Note: Express tension forces as positive (+) and compression forces as negative (-). A F₁₂ B F₂
Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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please explain how to solve and include FBD
![A cantilever truss supports three forces at joints along the top edge, as shown in the figure below. The forces
have magnitudes F₁ = 5 kip, F2 = 6 kip, and F3 = 10 kip. The truss is held in equilibrium by a pin at point
A and a roller at point G. The lengths for members DE, EF, and FG is s = 9 ft and for member AG is h = 15 ft.
Note that members BF and CE are vertical, and side ABCD is a straight line. The truss members are fabricated
from low-carbon steel with a yield strength of S₁ = ±46 ksi. Using the method of sections, determine the
minimum cross sectional areas for members AB, BF, and EF so that each one exhibits a safety factor of
SF = 3.9 with respect to yielding.
Note: Express tension forces as positive (+) and compression forces as negative (-).
h
A
G
F₁
F₂
B
F3
C
F
E
S
S
AAB
= number (rtol=0.01, atol=1e-05)
in²
ABF
number (rtol=0.01, atol=1e-05)
in²
AEF
=
number (rtol=0.01, atol=1e-05)
in²
S
D](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F68cfc78d-9a17-4a18-9125-7ed4df6070d3%2F5914153d-b43b-45ff-b839-25934f13007f%2Fxtcjxr9_processed.png&w=3840&q=75)
Transcribed Image Text:A cantilever truss supports three forces at joints along the top edge, as shown in the figure below. The forces
have magnitudes F₁ = 5 kip, F2 = 6 kip, and F3 = 10 kip. The truss is held in equilibrium by a pin at point
A and a roller at point G. The lengths for members DE, EF, and FG is s = 9 ft and for member AG is h = 15 ft.
Note that members BF and CE are vertical, and side ABCD is a straight line. The truss members are fabricated
from low-carbon steel with a yield strength of S₁ = ±46 ksi. Using the method of sections, determine the
minimum cross sectional areas for members AB, BF, and EF so that each one exhibits a safety factor of
SF = 3.9 with respect to yielding.
Note: Express tension forces as positive (+) and compression forces as negative (-).
h
A
G
F₁
F₂
B
F3
C
F
E
S
S
AAB
= number (rtol=0.01, atol=1e-05)
in²
ABF
number (rtol=0.01, atol=1e-05)
in²
AEF
=
number (rtol=0.01, atol=1e-05)
in²
S
D
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