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A cantilever truss supports three forces at joints along the top edge, as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F₂ = 6 kip, and F3 = 10 kip. The truss is held in equilibrium by a pin at point A and a roller at point G. The lengths for members DE, EF, and FG is s = 9 ft and for member AG is h = 15 ft. Note that members BF and CE are vertical, and side ABCD is a straight line. The truss members are fabricated from low-carbon steel with a yield strength of S₁ = ±46 ksi. Using the method of sections, determine the minimum cross sectional areas for members AB, BF, and EF so that each one exhibits a safety factor of SF 3.9 with respect to yielding. Note: Express tension forces as positive (+) and compression forces as negative (-). A F₁₂ B F₂

A cantilever truss supports three forces at joints along the top edge, as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F₂ = 6 kip, and F3 = 10 kip. The truss is held in equilibrium by a pin at point A and a roller at point G. The lengths for members DE, EF, and FG is s = 9 ft and for member AG is h = 15 ft. Note that members BF and CE are vertical, and side ABCD is a straight line. The truss members are fabricated from low-carbon steel with a yield strength of S₁ = ±46 ksi. Using the method of sections, determine the minimum cross sectional areas for members AB, BF, and EF so that each one exhibits a safety factor of SF 3.9 with respect to yielding. Note: Express tension forces as positive (+) and compression forces as negative (-). A F₁₂ B F₂

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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A cantilever truss supports three forces at joints along the top edge, as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F2 = 6 kip, and F3 = 10 kip. The truss is held in equilibrium by a pin at point A and a roller at point G. The lengths for members DE, EF, and FG is s = 9 ft and for member AG is h = 15 ft. Note that members BF and CE are vertical, and side ABCD is a straight line. The truss members are fabricated from low-carbon steel with a yield strength of S₁ = ±46 ksi. Using the method of sections, determine the minimum cross sectional areas for members AB, BF, and EF so that each one exhibits a safety factor of SF = 3.9 with respect to yielding. Note: Express tension forces as positive (+) and compression forces as negative (-). h A G F₁ F₂ B F3 C F E S S AAB = number (rtol=0.01, atol=1e-05) in² ABF number (rtol=0.01, atol=1e-05) in² AEF = number (rtol=0.01, atol=1e-05) in² S D
Transcribed Image Text:A cantilever truss supports three forces at joints along the top edge, as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F2 = 6 kip, and F3 = 10 kip. The truss is held in equilibrium by a pin at point A and a roller at point G. The lengths for members DE, EF, and FG is s = 9 ft and for member AG is h = 15 ft. Note that members BF and CE are vertical, and side ABCD is a straight line. The truss members are fabricated from low-carbon steel with a yield strength of S₁ = ±46 ksi. Using the method of sections, determine the minimum cross sectional areas for members AB, BF, and EF so that each one exhibits a safety factor of SF = 3.9 with respect to yielding. Note: Express tension forces as positive (+) and compression forces as negative (-). h A G F₁ F₂ B F3 C F E S S AAB = number (rtol=0.01, atol=1e-05) in² ABF number (rtol=0.01, atol=1e-05) in² AEF = number (rtol=0.01, atol=1e-05) in² S D
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