**Problem Statement:** A component with a rectangular cross-section measuring 25 mm by 75 mm is subject to a torsional moment of 20 kN·m about its axis and a compressive force of 400 kN along its axis. The component is made of aluminum, with a yield strength of 200 MPa in tension and 250 MPa in compression. Determine the safety factor using all applicable theories. **Detailed Explanation:** - **Cross-Section Specifications:** The component has a rectangular cross-section with dimensions of 25 mm and 75 mm. - **Forces Applied:** - **Torsional Moment:** The component experiences a torsional moment of 20 kN·m. - **Compressive Force:** A compressive force of 400 kN acts along the axis of the component. - **Material Properties:** The component is composed of aluminum: - Yield strength in tension: 200 MPa - Yield strength in compression: 250 MPa - **Objective:** Calculate the safety factor using all relevant theories, which may include Von Mises, Tresca, and other applicable stress analysis approaches. **Note:** The problem does not provide any diagrams or graphs. Therefore, a detailed verbal explanation is given for clarity.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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**Problem Statement:**

A component with a rectangular cross-section measuring 25 mm by 75 mm is subject to a torsional moment of 20 kN·m about its axis and a compressive force of 400 kN along its axis. The component is made of aluminum, with a yield strength of 200 MPa in tension and 250 MPa in compression. Determine the safety factor using all applicable theories.

**Detailed Explanation:**

- **Cross-Section Specifications:** The component has a rectangular cross-section with dimensions of 25 mm and 75 mm.

- **Forces Applied:**
  - **Torsional Moment:** The component experiences a torsional moment of 20 kN·m.
  - **Compressive Force:** A compressive force of 400 kN acts along the axis of the component.

- **Material Properties:** The component is composed of aluminum:
  - Yield strength in tension: 200 MPa
  - Yield strength in compression: 250 MPa

- **Objective:** Calculate the safety factor using all relevant theories, which may include Von Mises, Tresca, and other applicable stress analysis approaches.

**Note:** The problem does not provide any diagrams or graphs. Therefore, a detailed verbal explanation is given for clarity.
Transcribed Image Text:**Problem Statement:** A component with a rectangular cross-section measuring 25 mm by 75 mm is subject to a torsional moment of 20 kN·m about its axis and a compressive force of 400 kN along its axis. The component is made of aluminum, with a yield strength of 200 MPa in tension and 250 MPa in compression. Determine the safety factor using all applicable theories. **Detailed Explanation:** - **Cross-Section Specifications:** The component has a rectangular cross-section with dimensions of 25 mm and 75 mm. - **Forces Applied:** - **Torsional Moment:** The component experiences a torsional moment of 20 kN·m. - **Compressive Force:** A compressive force of 400 kN acts along the axis of the component. - **Material Properties:** The component is composed of aluminum: - Yield strength in tension: 200 MPa - Yield strength in compression: 250 MPa - **Objective:** Calculate the safety factor using all relevant theories, which may include Von Mises, Tresca, and other applicable stress analysis approaches. **Note:** The problem does not provide any diagrams or graphs. Therefore, a detailed verbal explanation is given for clarity.
Expert Solution
Step 1

Data given -

Rectangular cross section 225×75 mm2

Torsional moment = 20kN

Axial Compressive force = 400kN

Yield strength = 200 Mpa (tension)

Yield strength = 250 Mpa (compression)

 

Step 2

Mechanical Engineering homework question answer, step 2, image 1

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