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A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F₂ = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies 8 = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression.

A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F₂ = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies 8 = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F2 = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). A. F₂ F₁ B S 0 FL S E PAB = number (rtol=0.01, atol=1e-05) kip ? PAF = number (rtol=0.01, atol=1e-05) kip ? . PBC = number (rtol=0.01, atol=1e-05) kip ? PBF = number (rtol=0.01, atol=1e-05) kip PCD = number (rtol=0.01, atol=1e-05) kip ? PCF = number (rtol=0.01, atol=1e-05) kip ? PDE = number (rtol=0.01, atol=1e-05) kip ? PDF = number (rtol=0.01, atol=1e-05) kip PEF= number (rtol=0.01, atol=1e-05) kip h h
Transcribed Image Text:A scissors truss supports three forces at joints B, C, and D as shown in the figure below. The forces have magnitudes F₁ = 5 kip, F2 = 35 kip, and F3 = 25 kip. The truss is held in equilibrium by a pin at point A and a roller at point E. Note that sides ABC, CDE, AFD, and BFE are straight lines, and member CF is vertical. Joint F lies s = 15 ft to the right and h = 5 ft above joint A, and joint C lies h = 5 ft above joint F. Use the method of joints to determine the force in each member of the truss, and indicate whether they are in tension or compression. Note: Express tension forces as positive (+) and compression forces as negative (-). A. F₂ F₁ B S 0 FL S E PAB = number (rtol=0.01, atol=1e-05) kip ? PAF = number (rtol=0.01, atol=1e-05) kip ? . PBC = number (rtol=0.01, atol=1e-05) kip ? PBF = number (rtol=0.01, atol=1e-05) kip PCD = number (rtol=0.01, atol=1e-05) kip ? PCF = number (rtol=0.01, atol=1e-05) kip ? PDE = number (rtol=0.01, atol=1e-05) kip ? PDF = number (rtol=0.01, atol=1e-05) kip PEF= number (rtol=0.01, atol=1e-05) kip h h
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