A scientist is researching GS1, an enzyme with a relative molecular mass (Mr) of 78,000 present in a bacterium. The scientist has isolated two mutant strains of the bacterium as described below.
Strain A: In this strain the GS1 protein is completely non-functional. Analysis of strain A shows that it produces a shortened GS1 protein with an Mr of only 38,000. Strain B: This produces functional GS1, but the Kcat is somewhat reduced. Analysis shows it produces a lengthened form of GS1, with an Mr of about 86,000. The scientist determines the nucleotide sequence of the coding strand of the GS1 gene from strain A. It is identical to the GS1 sequence from the wild type gene except for a single change occurring approximately 1⁄3 of the way into the GS1 open reading frame. A small region of the GS1 sequence (including the site where the mutation occurs) from the wild type and mutant strains is shown below. Wild type TGTCCTCGGCCACAAGTTCTCTATC Strain A TGTCCTCGGCCACTAGTTCTCTATC How has this mutation produced the smaller GS1 protein in strain A? Using the genetic code (Fig. 1.), deduce the amino acid sequence of the wild type GS1 protein corresponding to the short piece of DNA shown above

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A scientist is researching GS1, an enzyme with a relative molecular mass (Mr) of 78,000 present in a bacterium. The scientist has isolated two mutant strains of the bacterium as described below.
Strain A: In this strain the GS1 protein is completely non-functional. Analysis of strain A shows that it produces a shortened GS1 protein with an Mr of only 38,000. Strain B: This produces functional GS1, but the Kcat is somewhat reduced. Analysis shows it produces a lengthened form of GS1, with an Mr of about 86,000. The scientist determines the nucleotide sequence of the coding strand of the GS1 gene from strain A. It is identical to the GS1 sequence from the wild type gene except for a single change occurring approximately 1⁄3 of the way into the GS1 open reading frame. A small region of the GS1 sequence (including the site where the mutation occurs) from the wild type and mutant strains is shown below. Wild type TGTCCTCGGCCACAAGTTCTCTATC Strain A TGTCCTCGGCCACTAGTTCTCTATC How has this mutation produced the smaller GS1 protein in strain A? Using the genetic code (Fig. 1.), deduce the amino acid sequence of the wild type GS1 protein corresponding to the short piece of DNA shown above
Second Letter
A
G
Phe UCU
UCC
|
UUU
UAU
UAC
UAA
UGU
UGC
UGA StopA
Trp G
Tyr
Cys U
U UUC
Ser
Stop
Stop
UUA
UCA
Leu
UUG
UCG
UAG
UGG
|
CUU
CU
CAU
His
CGU
C CUC
CUA
Leu cc
ССА
CGC
CGA
Pro
CAC
Arg
A
3rd
CAA
Gln
1st
CUG
CCG
CAG
CG
letter
|
| Lys
U letter
|
AGU
AGC
AUU
ACU
AAU
Asn
Ser
A AUC
AUA
lle
ACC
АCА
Thr
AAC
AAA
AGA
Arg
AUG
Met ACG
AAG
AGG
GCU
GCC
GAU
GAC
|
GUU
Asp
GGU
G GUC
Val
GCA
GGC Gly
Ala
GUA
GAA
GGA
A
Glu
GUG
GCG
GAG
GGG
Figure 1. The standard genetic code.
DUAC
Transcribed Image Text:Second Letter A G Phe UCU UCC | UUU UAU UAC UAA UGU UGC UGA StopA Trp G Tyr Cys U U UUC Ser Stop Stop UUA UCA Leu UUG UCG UAG UGG | CUU CU CAU His CGU C CUC CUA Leu cc ССА CGC CGA Pro CAC Arg A 3rd CAA Gln 1st CUG CCG CAG CG letter | | Lys U letter | AGU AGC AUU ACU AAU Asn Ser A AUC AUA lle ACC АCА Thr AAC AAA AGA Arg AUG Met ACG AAG AGG GCU GCC GAU GAC | GUU Asp GGU G GUC Val GCA GGC Gly Ala GUA GAA GGA A Glu GUG GCG GAG GGG Figure 1. The standard genetic code. DUAC
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