A sample of size n = 57 is drawn from a normal population. The sample mean is x = 58.5 and sample standard deviations = 9.5.Part: 0 / 2Part 1 of 2(a) Construct a 99.8% confidence interval for the population mean, μ. Round the answers to one decimal place.<μ<The 99.8% confidence interval isŚXolo11.⁰

The population is normally distributed.Sample size, Sample mean, Sample standard deviation, The…

Answered: A sample of size n = 57 is drawn from a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Gasoline Use A random sample of 25 drivers used on average 757 gallons of gasoline per year. The standard deviation of the population is 32 gallons. Part: 0 / 2 Part 1 of 2 (a) Find the 99% confidence interval of the mean for all drivers. Round intermediate answers to at least three decimal places. Round your final answers to the nearest whole number. ☐<μ< X Ś
Drill lifetime: A sample of 50 drills had a mean lifetime of 12.07 holes drilled when drilling a low-carbon steel. Assume the population standard deviation is 6.26. Part: 0/3 Part 1 of 3 (a) Construct a 95% confidence interval for the mean lifetime of this type of drill. Use tables or technology. Round your answers to at least two decimal places. D. X The confidence interval is S
Overweight Men For a random sample of 55 overweight men, the mean of the number of pounds that they were overweight was 31. The standard deviation of the population is 3.9 pounds. Use a graphing calculator and round the final answers to one decimal place. Part 1 of 4 The best point estimate of the mean is 31 pounds. Part: 1 / 4 Part 2 of 4 Find the 90% confidence interval of the mean of these pounds. <μ< X
data: FieldA and Fields af- 34.751, p-value e.001292 alternative hypothesis: true difference in means is not equal to 0 95 percent conf dence interval: sample estimates: mean of x mean of 13.98803 11.02686 Q. Based on the summary statistics calculate the missing t test statistic from the R output: t statistic = 3.583 Q. Give the set up for the 95% confidence interval for the difference in averages. Use the degrees of freedom from the R output (round down). Estimate ± Critical Value × Standard Error - 14 2.042 0.701 Q. Make a conclusion based on the previous results. There is convincing evidence the average percent of water by volume in the soil between Field A and Field B differs. Based on the p-value, the test rejects * the null hypothesis. The 95% confidence interval and point estimate indicate the Field A has more average percent by volume than Field B.
IQ scores: Scores on an IQ test are normally distributed. A sample of 20 1Q scores had standard deviation s=10. (a) Construct a 99% confidence interval for the population standard deviation o. Round the answ s to at least two decimal places. (b) The developer of the test claims that the population standard deviation is o=13. Does this confidence interval contradict this claim? Explain. Part: 0/ 2 Part 1 of 2 A 99% confidence interval for the population standard deviation is
Gasoline Use A random sample of 36 drivers used on average 741 gallons of gasoline per year. The standard deviation of the population is 33 gallons. Part: 0 / 2 Part 1 of 2 (a) Find the 95% confidence interval of the mean for all drivers. Round intermediate answers to at least three decimal places. Round your final answers to the nearest whole number. <µ< X 5
Hospital Noise Levels Noise levels at various area urban hospitals were measured in decibels. The mean of the noise levels in 36 randomly selected corridors was 61.2 decibels, and the standard deviation of the population was 7.3. Find the 99% confidence interval of the true mean. Round your answers to one decimal place. <μ <
Breaking Strength of Cable A special cable has a breaking strength of 800 pounds. The standard deviation of the population is 12 pounds. A researcher selects a sample of 23 cables and finds that the average breaking strength is 793 pounds. Can he reject the claim that the breaking strength is 800 pounds? Use the P-value method with a 0.05 level of significance. Assume that the variable is normally distributed. Use a graphing calculator. Part: 0/4 Part 1 of 4 (a) State the hypotheses and Identify the claim. Ho (Choose one) H₂: (Choose one) This hypothesis test is a (Choose one) test. 000-0 H G 民留〗f g E
Scores on an English test from 30 students in Class One has a mean of 33 and a standard deviation of 7.2. Scores on an English test from 40 students in Class Two has a mean of 39 and a standard deviation of 5.5. Assuming the two classes are independent, construct a 90%confidence interval for difference between the mean scores for Class One and Class Two. Round your answer to 3 decimal places. Base on the confidence interval, what conclusion can you draw? Group of answer choices (-8.530,-3.470) Group 2 is bigger (-8.530,-3.470) Group 1 is bigger (-8.639,-3.361) No conclusion (-8.639,-3.361) Group 2 is bigger (-6.769,-5.231) Group 2 is bigger
upper and lower limit
Find the left and right chi square values, then give the confidence interval. Sample Variance s 15.99 %3D Confidence Level c = 0.90 and Sample Size n = 13 and x %3D %3D At the 90 % level of confidence the population variance is between and (Round all answers to 3 decimal places)
Prison Sentences The average length of prison term in the United States for white collar crime is 34.9 months. A random sample of 40 prison terms indicated a mean stay of 28.8 months with a standard deviation of 8.9 months. At α=0.01, is there sufficient evidence to conclude that the average stay differs from 34.9 months? Use the P-value method. Use a graphing calculator. Find the P-value. Round the answer to at least four decimal places. P-value=

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