Efficient manufacturing: Efficiency experts study the processes used to manufacture items in order to make them as efficient as possible. One of the stepsused to manufacture a metal clamp involves the drilling of three holes. In a sample of 100 clamps, the mean time to complete this step was 56.9 seconds.Assume that the population standard deviation is = 8 seconds. Round the critical value to no less than three decimal places.Part: 0 / 2Part 1 of 2(a) Construct a 95% confidence interval for the mean time needed to complete this step. Round the answer to at least one decimal place.A 95% confidence interval for the mean is<μ<XŚalo

The following information has been given: n=100x¯=56.9σ=8

Answered: Efficient manufacturing: Efficiency…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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12:14 PM Thu 4 Mar Ims.ub.edu.sa Remaining Time: 45 minutes, 53 seconds. Question Completion Status: Question 5 The following table represents the age (years) of participants of "corona virus symptoms criteria" study. Frequency Age (years) Cumulative frequency 10-19 10 10 20-29 35 45 30-39 24 69 40-49 11 80 50-60 20 100 What the median class in this study? 40-49 30-39 50-60 10-19
question 20 The amount of time that people spend at Grover Hot Springs is normally distributed with a mean of 71 minutes and a standard deviation of 16 minutes. Suppose one person at the hot springs is randomly chosen. Let X = the amount of time that person spent at Grover Hot Springs . Round all answers to 5 decimal places where possible. c. The park service is considering offering a discount for the 8% of their patrons who spend the least time at the hot springs. What is the longest amount of time a patron can spend at the hot springs and still receive the discount ? minutes.d. Find the Inter Quartile Range (IQR) for time spent at the hot springs.Q1: minutesQ3: minutesIQR: minutes
Question 11
Question 10 く Suppose that we are studying the amount of time customers wait in line at the checkout at the Gap and Old Navy. The avérage wait time at both stores is five minutes. At the Gap, the standard deviation for the wait time is 2 minutes; at Old Navy the standard deviation for the wait time is 5 minutes. Because Old Navy has a higher standard deviation, we know that there is Select an answer v in the wait times at Old Navy. Overall, wait times at Old Navy are Select an answer v from the average; wait times at the Gap are Select an answer v near the average.
Question 36 An honor society on campus only accepts the top 13% of students (according to GPA). If the GPAS of all students on campus are known to be a normally distributed with a mean of 2.99 and a standard deviation of 0.45, determine the minimum GPA a student must achieve in order to be admitted to the honor society. Round the solution to two decimal places, if necessary. A minimum GPA of is required for admission to the honor society.
Question 8, section 6.1
QUESTION 6 The amount of time for an oil change at a particular service station is normally distributed with a mean of 23.2 minutes and a standard deviation of 3.8 minutes. Find each value below. Round all answers to two decimal places. Type the number only; do not include units. What length of time separates the top 3% of oil change durations at this station? minutes What length of time separates the bottom 15% of oil change durations at this station? minutes What are the two lengths of time that have, between them, the middle 90% of oil change durations at this station? (You will find two values, a lower endpoint and an upper endpoint. Between these values is the middle 90% of observations for this distribution.) Lower endpoint: Upper endpoint: minutes minutes
Question 3 of 14 (12 points) Attempt 1 of 3 View question in a popup 6.3 Section Exercise 15 (ca Coffee: The National Coffee Association reported that 64% of U.S. adults drink coffee daily. A random sample of 225 U.S. adults is selected. Round your answers to at least four decimal places as needed. Part: 0/ 6 民 Part 1 of 6 (a) Find the mean A. The mean lln is ola
Question 9 The heights of 16-month-old oak seedlings are normally distributed with a mean of 31.5 cm and a standard deviation of 11 cm. What is the range of heights between which 5% of the seedlings will grow? Show all your work using proper mathematical notations.

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