Get an education: In 2012 the General Social Survey asked 831 adults how many years of education they had. The sample mean was 7.91 years with astandard deviation of 7.95 years.Part: 0/2Part 1 of 2(a) Construct a 95% confidence interval for the mean number of years of education. Round the answers to two decimal.places.A 95% confidence interval for the mean number of years of education isSkip PartCheckX<μ<ŚMacBook AirSave For LaterUSubmit AssignmentL50022023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility

Solution-:Given: We want to construct a 95% C.I. for the mean number of years…

Answered: Get an education: In 2012 the General…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Time in surgery: Records at a hospital show that a certain surgical procedure takes an average of 165.6 minutes with a standard deviation of 9.1 minutes. If the data are approximately bell-shaped, between what two values will about 68% of the data fall? About 68% of the data will fall between and
Coffee: The National Coffee Association reported that 65% of U.S. adults drink coffee daily. A random sample of 300 U.S. adults is selected. Round your answers to at least four decimal places as needed. Part 1 of 6 (a) Find the mean . is 0.6500 The mean Alternate Answer: p The mean Part: 1/6 Part 2 of 6 is 0.65. 15 (b) Find the standard deviation . The standard deviation d is Español 00
Overweight Men For a random sample of 70 overweight men, the mean of the number of pounds that they were overweight was 32. The standard deviation of the population is 4.4 pounds. Part: 0 / 4 0 of 4 Parts Complete Part 1 of 4 (a) The best point estimate of the mean is how many pounds?
Number of Jobs A sociologist found that in a sample of 49 retired men, the average number of jobs they had during their lifetimes was 6.8 . The population standard deviation is 2.4 . Use a graphing calculator and round the answers to one decimal place. Part: 0 / 4 0 of 4 Parts Complete Part 1 of 4 The best point estimate of the mean is . ??
The mean number of eggs per person eaten in the United States is 252 and the standard deviation is 68. Do college students eat more than the average? The 45 college students surveyed averaged 281 eggs per person. What can be concluded at the 0.05 level of significance? H0: = 252 Ha: _____________ 252 Test statistic: __________ p-Value =__________ Reject/Fail to reject H0?______________ Conclusion: There is____________ evidence to make the conclusion that the population mean number of eggs consumed college students per year is more than 252 eggs per student per year. p-Value Interpretation: If the mean number of eggs consumed per year for college students is equal to_________ and if another study was done with a new randomly selected group of 45 college students, then there is a ____________ percent chance that the average number of eggs consumed per year for this new sample would be greater than_____________ . Level of significance…
Lunch break: In a recent survey of 654 working Americans ages 25 - 34 , the average weekly amount spent on lunch as $44.36 with standard deviation $2.74 . The weekly amounts are approximately bell-shaped. Part: 0 / 3 0 of 3 Parts Complete Part 1 of 3 (a) Estimate the percentage of amounts that were between $44.36 and $49.84 . Round the answer to one decimal place.
Hospital Noise Levels Noise levels at various area urban hospitals were measured in decibels. The mean noise level in 170 ward areas was 51.6 decibels, and the population standard deviation is 5.2. Find the 95% confidence interval of the true mean. Round your answers to at least one decimal place.
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For data of discussion 1 refer to this picture What is the best point estimate for your survey question that you used in Discussion 1? Be sure to include both the correct notation (symbol) and the value. Construct a confidence interval for the responses to your survey. Assume that you do not know the population standard deviation. Indicate your level of confidence and the corresponding critical value. What is the margin of error? If we would increase the sample size to 500 students, what would happen to your margin of error?
A researcher is interested in finding a 90% confidence interval for the mean number of times per day that college students text. The study included 149 students who averaged 34.2 texts per day. The standard deviation was 18.6 texts. Round to 3 decimals. b. With 90% confidence the population mean number of texts per day is between _______ and ________ texts a day.
In a survey, 28 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $44 and standard deviation of $6. Construct a confidence interval at a 98% confidence level.Give your answers to one decimal place._______________ ± _______________Interpret your confidence interval in the context of this problem.

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