A sample of a substance with the empirical formula XCI2 weighs 0.5719 g. When it is dissolved in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.2191 g. The chemical reaction is XCI2 + 2 AgNO3—2AgCl + X(NO3)2 (a) Calculate the formula mass of XCI2. Formula mass XCI2 = g mol-1 (b) Calculate the atomic mass of X. Atomic mass X = g mol-1
A sample of a substance with the empirical formula XCI2 weighs 0.5719 g. When it is dissolved in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.2191 g. The chemical reaction is XCI2 + 2 AgNO3—2AgCl + X(NO3)2 (a) Calculate the formula mass of XCI2. Formula mass XCI2 = g mol-1 (b) Calculate the atomic mass of X. Atomic mass X = g mol-1
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![### Determination of Empirical Formula
A sample of a substance with the empirical formula XCl₂ weighs 0.5719 g. When dissolved in water, all its chlorine is converted to insoluble AgCl by adding an excess of silver nitrate. The mass of the resulting AgCl is found to be 1.2191 g. The chemical reaction can be represented as:
\[ \text{XCl}_{2} + 2 \text{AgNO}_{3} \rightarrow 2 \text{AgCl} + \text{X(NO}_{3}\text{)}_{2} \]
Based on this reaction, solve the following questions:
**(a) Calculate the formula mass of XCl₂.**
\[ \text{Formula mass XCl}_{2} = \boxed{\hspace{4em}} \text{ g mol}^{-1}\]
**(b) Calculate the atomic mass of X.**
\[ \text{Atomic mass X} = \boxed{\hspace{4em}} \text{ g mol}^{-1}\]
---
**Explanation:**
1. **Determination of Formula Mass of XCl₂:**
To determine the formula mass, you need to identify the masses of the individual elements present in the compound XCl₂ and sum them. The molecular mass of AgCl is used in conjunction with stoichiometric relationships from the reaction to find any unknowns.
2. **Determination of Atomic Mass of X:**
By utilizing the known weights from the reaction and the stoichiometry of the balanced chemical reaction, the atomic mass of element X can be deduced.
Understanding the stoichiometry and being able to convert grams to moles (and vice versa) are crucial skills required to solve these problems efficiently.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4126b89b-6ee3-437f-8fcf-aa0e90855818%2Fb9b4400d-4db1-4d92-841f-85dbae7090b6%2Feukxdab_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Determination of Empirical Formula
A sample of a substance with the empirical formula XCl₂ weighs 0.5719 g. When dissolved in water, all its chlorine is converted to insoluble AgCl by adding an excess of silver nitrate. The mass of the resulting AgCl is found to be 1.2191 g. The chemical reaction can be represented as:
\[ \text{XCl}_{2} + 2 \text{AgNO}_{3} \rightarrow 2 \text{AgCl} + \text{X(NO}_{3}\text{)}_{2} \]
Based on this reaction, solve the following questions:
**(a) Calculate the formula mass of XCl₂.**
\[ \text{Formula mass XCl}_{2} = \boxed{\hspace{4em}} \text{ g mol}^{-1}\]
**(b) Calculate the atomic mass of X.**
\[ \text{Atomic mass X} = \boxed{\hspace{4em}} \text{ g mol}^{-1}\]
---
**Explanation:**
1. **Determination of Formula Mass of XCl₂:**
To determine the formula mass, you need to identify the masses of the individual elements present in the compound XCl₂ and sum them. The molecular mass of AgCl is used in conjunction with stoichiometric relationships from the reaction to find any unknowns.
2. **Determination of Atomic Mass of X:**
By utilizing the known weights from the reaction and the stoichiometry of the balanced chemical reaction, the atomic mass of element X can be deduced.
Understanding the stoichiometry and being able to convert grams to moles (and vice versa) are crucial skills required to solve these problems efficiently.
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