In an experiment, 0.2490 g of sodium bicarbonate, NaHCO3(s) was allowed to react with excess hydrochloric acid, HCl(aq), as per the below balanced chemical equation. At the end of the experiment, 0.1548 g of sodium chloride, NaCl(aq) was collected. Calculate the theoretical yield of NaCl(aq) and the % yield of NaCl(aq). NaHCO3(s)+HCl(aq)---> NaCl(aq)+CO2(g)+H2O(l)
In an experiment, 0.2490 g of sodium bicarbonate, NaHCO3(s) was allowed to react with excess hydrochloric acid, HCl(aq), as per the below balanced chemical equation. At the end of the experiment, 0.1548 g of sodium chloride, NaCl(aq) was collected. Calculate the theoretical yield of NaCl(aq) and the % yield of NaCl(aq).
NaHCO3(s)+HCl(aq)---> NaCl(aq)+CO2(g)+H2O(l)
In the given question we have to calculate the percent yield of NaCl in the following reaction,
first of all, we have to calculate the mole of sodium bicarbonate then applying mole ratio to calculate the moles of NaCl to calculate the theoretical yield of NaCl.
then calculate the percent yield by using actual yield of NaCl.
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