Upon reaction of 1.27 g of copper sulfate with excess zinc metal, 0.513 g copper metal was obtained as an'experimental result according to the equation: CuSOg(aq) + Zn(s) Cu(s) + ZNSO4(aq) Before the experiment was carried out the following calculation was completed to predict the maximum amount of copper that could be isolated. The answer was 0.506 g of Cu. mol Cuso, mol Cu g Cu Cuso, 1 mol Cuso, 1 mol Cu 63.55 g Cu 1 mol Cu 159.62 g CuSO, 1 mol CuSO, What is the percent yield? report your answer to the tenths place, L.e. one decimal place

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Upon reaction of 1.27 g of copper sulfate with excess zinc metal, 0.513 g copper metal was obtained as an experimental result according to the equation:
CuSO4(aq) + Zn(s) → Cu(s) + ZNSO4(aq)
Before the experiment was carried out the following calculation was completed to predict the maximum amount of copper that could be isolated. The answer was 0.506 g of Cu.
mol
E Cuso,
mol Cu
g Cu
Cuso,
1 mol Cuso,
1 тol Cu
63.55 g Cu
159.62 g CuSO4
1 mol CuSO,
1 тol Cu
What is the percent yield?
report your answer to the tenths place, i.e. one decimal place.
Transcribed Image Text:Upon reaction of 1.27 g of copper sulfate with excess zinc metal, 0.513 g copper metal was obtained as an experimental result according to the equation: CuSO4(aq) + Zn(s) → Cu(s) + ZNSO4(aq) Before the experiment was carried out the following calculation was completed to predict the maximum amount of copper that could be isolated. The answer was 0.506 g of Cu. mol E Cuso, mol Cu g Cu Cuso, 1 mol Cuso, 1 тol Cu 63.55 g Cu 159.62 g CuSO4 1 mol CuSO, 1 тol Cu What is the percent yield? report your answer to the tenths place, i.e. one decimal place.
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