A sample of 1500 computer chips revealed that 27 % of the chips fail in the first 1000 hours of their use. The company's promotional literature claimed that 30 % failin the first 1000 hours of their use. Is there sufficient evidence at the 0.02 level to dispute the company's claim?State the null and alternative hypotheses for the above scenario.田 TablesE KeypadAnswer

Given : A sample of 1500 computer chips revealed that 27 % of the chips fail in the first 1000 hours…

Answered: A sample of 1500 computer chips…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Previously, 11.2% of workers had a travel time to work of more than 60 minutes. An urban economist believes that the percentage has increased since then. She randomly selects 85 workers and finds that 11 of them have a travel time to work that is more than 60 minutes . Test the economist's belief at the a= 0.1 level of significance What are the null and alternative hypotheses? what are the null and alternative hypotheses? Because np0(1-p0)= < ? 10, Find the P-value.
The National Institute of Mental Health published an article stating that in any one-year period, approximately 8.8% of American adults suffer from depression or a depressive illness. Suppose that in a survey of 2000 people in a certain city, 11.3% of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that city suffering from depression or a depressive illness is more than the 8.8% in the general adult American population. Test the relevant hypotheses using a 5% level of significance. Give answer to at least 4 decimal places. a. What are the correct hypotheses? H0: H1: b.) Based on the hypotheses, find the following: c.) Test Statistic = d.) p-value = e.) Based on the above we choose to________________ f.) The correct summary would be:____________ that the true proportion of people in that city suffering from depression or a depressive illness is more than the percent in the general…
A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 80%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 80% of married couples. In a random sample of 215 married couples who completed her program, 180 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. A. State the null hypothesis Hoand the alternative hypothesis H1. Ho: H1: B. Find the value of the test statistic. (Round to three or more decimal places.) C. Find the critical value. (Round to three or more decimal places.) D. Is there enough evidence to support the marriage counselor's claim that the proportion of married couples for whom her program…
Previously, 3% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 3% today. She randomly selects 145 pregnant mothers and finds that 3 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.1 level of significance. What are the null and alternative hypotheses? Họ: P = 0.03 versus H4: p < 0.03 (Type integers or decimals. Do not round.) Because npo (1- Po) =|| 10, the normal model V be used to approximate the P-value. (Round to one decimal place as needed.)
A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 79%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 79% of married couples. In a random sample of 250 married couples who completed her program, 205 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor's claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H₁. H₂ : D H₁ : 0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) 0 (e) Is there enough…
USA Today reported that about 47% of the general consumer population in the United States is loyal to the automobile manufacturer of their choice. Suppose Chevrolet did a study of a random sample of 1007 Chevrolet owners and found that 482 said they would buy another Chevrolet. Does this indicate that the population proportion of consumers loyal Chevrolet is more than 47%? Use a = 0.01. (a) What is the level of significance? State the null and alternate hypotheses. O Ho: P = 0.47; H,: p 0.47 O Ho: p > 0.47; H,: p = 0.47 O Ho: p = 0.47; H1: p + 0.47 (b) What sampling distribution will you use? O The Student's t, since np 5 and ng > 5. O The standard normal, since np 5 and ng > 5. What is the value of the sample test statistic? (Round your answer to two decimal places.) (c) Find the P-value of the test statistic. (Round your answer to four decimal places.) Sketch the sampling distribution and show the area corresponding to the P-value.
An education researcher claims that at most 4% of working college students are employed as teachers or teaching assistants. In a random sample of 600 working college students, 6% are employed as teachers or teaching assistants. At a=0.10, is there enough evidence to reject the researcher's claim? Complete parts (a) through (e) below. Identify the claim in this scenario. Select the corect choice below and fill in the answer box to complete your choice. (Type an integer or a decimal. Do not round.) %. O A. The percentage of working college students who are employed as teachers or teaching assistants is not O B. At most % of working college students are employed as teachers or teaching assistants. OC. More than % of working college students are employed as teachers or teaching assistants. O D. % of working college students are employed as teachers or teaching assistants. Let p be the population, proportion of successes, where a success is a working college student who is employed as a…
A December 2017 Gallup Poll reported that 43% of Americans use the internet for an hour or more each day. You suspect that a greater proportion of students at your school use the internet that much. You take a random sample of 60 students and find that 36 of them use the internet for an hour or more each day. Assume your school has more than 600 students. You will test the hypotheses H, : p = 0.43, H,:p>0.43 , where p= the true proportion of students at your school who use the internet for an hour or more each day. Which of the following gives the correct test statistic for this test? 0.43 - 0.6 Z = (0.6)(0.4) 60 0.43-0.6 (0.6)(0.4) 600 0.6-0.43 (0.6)(0.4) 60 0.6 - 0.43 (0.43)(0.57) 60 36 - 60 (36)(24) 60
A demographer wants to know what proportion of women in different countries dye their hair. They take a random sample of women from Korea and another random sample of women from China. In Korea, 47% dyed their hair. In China, 56% dyed their hair. (a) What hypotheses would the demographer use to test if women in China are more likely to dye their hair than women in Korea? H0: pChina=pKorea vs. Ha: pChina ≠ pKoreaH0: pChina - pKorea = 0 vs. Ha: pChina - pKorea > 0 H0: μChina-μKorea = 0 vs. Ha: μChina-μKorea ≠ 0H0: pChina-pKorea = 0.09 vs. Ha: pChina-pKorea ≠ 0.09H0: μChina = 0.56 vs. Ha: μKorea = 0.47 (b) Suppose their test yielded a p-value of 0.079. What does this mean in the context of the test? We are 7.9% confident that the results of our test are correct.If the women of two countries have the same rates of coloring their hair, the probability of getting a difference at least this large is 0.079. If we take another sample, the probability of getting the same p̂China and…
The National Institute of Mental Health published an article stating that in any one-year period, approximately 8.8% of American adults suffer from depression or a depressive illness. Suppose that in a survey of 2000 people in a certain city, 11.3% of them suffered from depression or a depressive illness. Conduct a hypothesis test to determine if the true proportion of people in that city suffering from depression or a depressive illness is more than the 8.8% in the general adult American population. Test the relevant hypotheses using a 5% level of significance. Give answer to at least 4 decimal places. a. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) H0: H1: b. Based on the hypotheses, find the following: c. Test Statistic = d. p-value = e. Based on the above we choose to:_____________ f. The correct summary would be: ____________ that the true proportion of people in that city suffering from depression or a…
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