A sample of 1100 computer chips revealed that 76% of the chips fail in the first 1000 hours of their use. The company's promotional literature claimed that less than 79% fail in the first 1000 hours of their use. Is there sufficient evidence at the 0.02 level to support the company's claim? State the null and alternative hypotheses for the above scenario.
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A: State the null and alternate hypothesis. Null Hypothesis: There is no association between the…
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A: From the provided information, Sample size (n) = 900 Out of which 17 patients taking a prescription…
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A:
Q: Only 14% of registered voters voted in the last election. Will voter participation decline for the…
A: sample size(n)=398 x=44 significance level(α)=0.10 sample proportion(p^)=44398≅0.1106
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A: Given data is appropriate for testing of hypothesis for z-test for single proportions (n>30) It…
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A: Given data issample size(n)=205x=164sample proportion(p^)=xn=164205=0.8significance level(α)=0.05
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A: (C). It is given that is 2-sided hypothesis tests. To test the hypotheses using a z-proportional…
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A: Solution Step 1
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A: Since you have posted multiple questions we will provide the solution onlyto the first question as…
Q: State the null and alternative hypotheses for the above scenario.
A: Population proportion of the test tubes contains error P = 68% =0.68 Sample of size n= 100 with…
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Q: A marriage counselor has traditionally seen that the proportion p of all married couples for whom…
A: From the provided information,Sample size (n) = 210From which 167 of them stayed together.Level of…
Q: A doctor used to believe that babies were equally likely to be born any day of the week, but with…
A: The following solution is given below:
Q: A newsletter publisher believes that over 68%68% of their readers own a personal computer. Is there…
A: Null hypothesis: Alternative hypothesis:
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A: It is given that the A person claims to have extrasensory powers. She correctly identifies the…
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A:
Q: Ten years ago, 53% of American families owned stocks or stock funds. Sample data collected by the…
A: 1) The hypotheses for the test are given below. Null hypothesis: H0: p = 0.53 Alternative…
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A: The margin of error is, E = 0.0525, If the prior information is unknown, assume the value of sample…
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A: Solution: Given information: n1= 562 Sample size of wildfires in south n2= 548 Sample size of…
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Q: In 2011, Brand A MP3 Players had 45% of the market, Brand B had 35%, and Brand C had 20%. This year…
A: Introduction: Denote p1, p2, and p3, as the true proportions of Brand A, Brand B, and Brand C MP3…
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A: In hypothesis testing, we start by stating the null hypothesis (H0) and the alternative hypothesis…
Q: A marriage counselor has traditionally seen that the proportion p of all married couples for whom…
A: given data clim : p > 0.76n = 215x = 171α = 0.05p^ = xn = 171215 = 0.7953
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A: For Hispanic adults, sample size n1 = 640 and sample proportion is 4.6% = 0.046 For white adults,…
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A: The hypothesized proportion is 0.16.
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A: It is given that Microsoft would like to advertise more than 30% of all its customers who have more…
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A: use the theory of testing of proportion .using Z test
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A: Given data, n=140 x=51 P=27.1% sample proportion(p)=x/n= 51/140 =0.3643
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A: Given n1=100n2=100p1^=20%=20100=0.2p2^=30% =30100=0.3
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Q: (a) State the null hypothesis Ho and the alternative hypothesis H₁. H:0 H₁:0 (b) Determine the type…
A: It is given that Population proportion, p = 80% = 0.80 Favourable cases, X = 178 Sample size, n =…
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A: Given that N=300p=0.46 α=.01
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A: From the given information the 99% confidence interval was ( 0.443, 0.411)
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A: Given that Sample size n =205 Favorable cases x =171 Sample proportion p^=x/n =171/205 =0.8341
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A: The give is, 11.2% of workers had a travel time to work for more than 60 minutes. X=11 and n=85…
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A: Given : You are conducting a study to see if the proportion of voters who prefer the Democratic…
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A: Note- Since you have posted a question with multiple sub-parts, we will solve the first three…
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- Previously, 3% of mothers smoked more than 21 cigarettes during their pregnancy. An obstetrician believes that the percentage of mothers who smoke 21 cigarettes or more is less than 3% today. She randomly selects 145 pregnant mothers and finds that 3 of them smoked 21 or more cigarettes during pregnancy. Test the researcher's statement at the a = 0.1 level of significance. What are the null and alternative hypotheses? Họ: P = 0.03 versus H4: p < 0.03 (Type integers or decimals. Do not round.) Because npo (1- Po) =|| 10, the normal model V be used to approximate the P-value. (Round to one decimal place as needed.)A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 79%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 79% of married couples. In a random sample of 250 married couples who completed her program, 205 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor's claim at the 0.05 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H and the alternative hypothesis H₁. H₂ : D H₁ : 0 (b) Determine the type of test statistic to use. (Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) 0 (d) Find the p-value. (Round to three or more decimal places.) 0 (e) Is there enough…A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 77%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 77% of married couples. In a random sample of 215 married couples who completed her program, 167 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.10 level of significance? Perform a one-tailed test. Then complete the parts below. Carry your intermediate computations to three or more decimal places. (If necessary, consult a list of formulas.) (a) State the null hypothesis H0 and the alternative hypothesis H1. H0: H1: (b) Determine the type of test statistic to use. ▼(Choose one) (c) Find the value of the test statistic. (Round to three or more decimal places.) (d) Find the p-value. (Round to three…
- An experimenter has prepared a drug-dose level that he claims will induce sleep for at least 70% of people suffering from insomnia. After examining the dosage we feel that his claims regarding the effectiveness of his dosage are too high. In an attempt to disprove his claim, we administer his prescribed dosage to 80 insomniacs and observe that 51 of them have had sleep induced by the drug dose. Is there enough evidence to refute his claim at the 5% level of significance? a) state null and alternate hypotheses b) find the test statistic and rejection region c) state your conclusionA newsletter publisher believes that more than 79% of their readers own a personal computer. Is there sufficient evidence at the 0.02 level to substantiate the publisher's claim? State the null and alternative hypotheses for the above scenario.A marriage counselor has traditionally seen that the proportion p of all married couples for whom her communication program can prevent divorce is 78%. After making some recent changes, the marriage counselor now claims that her program can prevent divorce in more than 78% of married couples. In a random sample of 240 married couples who completed her program, 189 of them stayed together. Based on this sample, is there enough evidence to support the marriage counselor’s claim at the 0.10 level of significance?Perform a one-tailed test. Then complete the parts below.
- A hospital director believes that above 55% of the lab reports contain errors and feels an audit is required. A sample of 120 reports found 72 errors. Is there sufficient evidence at the 0.02 level to substantiate the hospital director's claim? State the null and alternative hypotheses for the above scenario.Research by Harvard Medical School experts suggests that boys are more likely to grow out of childhood asthma when they hit their teenage years. Scientists followed over 1000 children between ages of 5 and 12, all of whom had mild to moderate asthma. By the age of 18, 14% of girls and 27% of boys seems to have grown out of asthma. Suppose their analysis was based on 500 girls and 500 boys.(a) Do the hypothesis testing at 5% level of significance to test whether the proportion of boys who grow out of asthma in their teenage years is more than that of girls.(b) Find beta(0.30, 0.15)A nationwide survey of working adults indicates that out of 100 adults, 50 of them are satisfied with their jobs. The president of a large company believes that more than this number of employees at his company are satisfies with their jobs. To test his belief, he surveys a random sample of 100 employees, and 59 of them report that they are satisfied with their jobs. Do you support president's statement about the employee’s satisfaction? (Use a= 0.05 level of significance.) Find H0 and Ha. Find Test Statistic Identify Decision Identify Conclusion
- According to securelist, 71.8% of all email sent is spam. A system manager at a large corporation believs that the percentage at his company may be 80%. he examines a random sample of 500 emails received at an email server, and finds that 382 of the messages are spam. a. State the appropriate null and alternate hypotheses. b. Compute the test statistic z. c. Using a=0.5 can you conclude the percentage of emails that are spam differs from 80%?Using the proper symbols, write the null and alternative hypotheses for each scenario below. a) A very large study showed that aspirin reduced the rate of first heart attacks by 44%. A pharmaceutical company thinks they have a drug that will be more effective than aspirin and plans to do a randomized clinical trial to test the new drug. b) In the 1950’s, only about 40% of high school graduates went on to college. Has the percentage changed?According to the national Center for health statistics, 74% of American women have been married by the age of 30. Suppose in a survey of 125 American women ( who are at least 30) and it is found that 91 of them were married at least once. Does the survey provide significant evidence that less than 74% of American women have been married by the age of 30? Test the relevant hypotheses at a significance level of 0.10.