←A random sample of n=25 is obtained from a population with variance o2, and the sample mean is computed. Test the null hypothesis Ho: μ = 100 versus the alternative hypothesisH₁: > 100 with α=0.01. Compute the critical value xc and state your decision rule for the options below.a. The population variance is o2 = 196.b. The population variance is o² = 625.C.The population variance is o² = 900.d. The population variance is o2 = 700.a xcReject Ho if the sample mean is(Round to four decimal places as needed.)b. xc =(Round to four decimal places as needed.)(Round to four decimal places as needed.)Reject Ho if the sample mean is(Round to four decimal places as needed.)greater than or equal toless than or equal tonot equal toequal toless thangreater thanboth have same optionNext

The null hypothesis : Ho:u = 100 versus the alternative hypothesis, H1:u > 100 Also, n=25 and α…

Answered: A random sample of n=25 is obtained…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Experiment 3: Fifteen female CSCC students and 10 male CSCC students are randomly selected to determine if the mean time studying for females is significantly more than the mean study time for males. It can be assumed that all study times are normally distributed. Are these samples independent or dependent? Find the null and alternative hypothesis. H0: Ha:
a. What are the sample estimates of β0,β1,and β2? b. What is the least squares prediction equation? c. FindSSE,MSE,and standard deviation . Interpret the standard deviation in the context of the problem. d. Test H0: β1=0 against Ha: β1≠0.Use α=0.01. e. Use a 95% confidence interval to estimate β2. f. Find R2 and R^2_a and interpret these values. g. Find the test statistic for testing H0: β1=β2=0. h. Find the observed significance level of the test in part g.interpret the result.
Let X denote the sample average for a random sample with mean uu and variance 02. Consider the following estimator for u: W=n+2/n+1°X Is W as consistent estimator of u? a. Yes b. No c. It depends
Suppose X1,., Xn, for n > 1, are sampled independently from a distribution with mean u and variance o?. Consider the following four estimators for X1+ Xn 2 X1 2 п(п + 1) i=1 a. Calculate the bias of each of these estimators. b. Calculate the standard error for each estimator. c. Which estimator would you choose to use? (Give a reason for your choice).
The yield per tract in a certain region of farmland is known to have a populationstandard deviation of 13 bushels. Using the old seed variety, the population mean yield μwas 39 bushels. A farmer tests a new seed variety on a random sample of 36 tracts, andfinds a sample mean yield of 45.2 bushels. Is the population mean yield using the newseed variety different from 39? Use α= 0.10.a. State the null hypothesis . __________________State the alternative hypothesis.____________________b. Find the test statistic. _____ c. Find the P-value for the test. _____________
The null and alternate hypotheses are: He: P₁ =H₂ H₁ H₁ #P₂ A random sample of 15 observations from the first population revealed a sample mean of 350 and a sample standard deviation of 12. A random sample of 17 observations from the second population revealed a sample mean of 342 and a sample standard deviation of 15. The population variances are assumed to be equal. At the 0.10 significance level, is there a difference in the population means? a. Is this a one-tailed or a two-tailed test? O One-tailed test. OTwo-tailed test. b. State the decision rule. (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.) The decision rule is to reject H0 if t
Answers: 2. t = .656, do not reject Ho: there is no evidence that this year's students are performing differently than students in previous years. 3. chi-square = 7.997, Do not reject H0; no evidence that the variance is significantly less than 175. chi-square = 11.250, Do not reject H0; no evidence that the variance is significantly greater than 175. 4. 3.973 to 13.5219
Two samples were drawn independently from two normal populations. Sample 1: 11.6, 11.35, 10.1, 10.85, 10.35, 10.6, and 11.1.Sample 2: 5.85, 8.85, 9.85, 11.85 and 7.85.Test to determine whether the means of the two population differs (use α=0.05).
Fresh Mart QQ's profit on each delivery is estimated by RM P, where the random variable P has mean u and variance 1.92. According to previous record, the value of u used to be 0.85. Manager suspects that this value has increased. In order to test at the 5% significance level whether the value of u has increased, a random sample of 50 delivery transaction is chosen. Assume the variance of P is unchanged. Given that Ep 59. Find the unbiased estimates of the population mean. Stating the null and alternative hypotheses, test at 5% significance level on whether the manager's suspicion is true. The alternative hypothesis for a test is stated as below: H:µ # 30 State the null hypothesis and determine whether this test is one-tail test or two- tail test hypothesis.
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A transect is an archaeological study area that is 1/5 mile wide and 1 mile long. A site in a transect is the location of a significant archaeological find. Let x represent the number of sites per transect. In a section of Chaco Canyon, a large number of transects showed that x has a population variance ?2 = 42.3. In a different section of Chaco Canyon, a random sample of 19 transects gave a sample variance s2 = 46.9 for the number of sites per transect. Use a 5% level of significance to test the claim that the variance in the new section is greater than 42.3. Find a 95% confidence interval for the population variance. (b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.)- 19.96 What are the degrees of freedom? -18 (c) Find or estimate the P-value of the sample test statistic. P-value > 0.1000.050 < P-value < 0.100 0.025 < P-value < 0.0500.010 < P-value < 0.0250.005 < P-value < 0.010P-value < 0.005…

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