A snack food manufacturer estimates that the variance of the number of grams of carbohydrates in servings of its tortilla chips Is 1claim and finds that a random sample of 22 servings has a variance of 0.95. At a= 0.01, is there enough evidence to reject the manufacturer's claim? Assume thepopulation is normally distributed. Complete parts (a) through (e) below.2.H, o>1.112.H o<1.11 (Claim)aourses(b) Find the critical value(s) and identify the rejection region(s).The critical value(s) is(are) 8.03,41.40(Round to two decimal places as needed. Use a comma to separate answers as needed.)rse HomesignmentsChoose the correct statement below and fill in the corresponding answer boxes.adebookOA The rejection region is x>2.hapter ContentsOB. The rejection region is x&c The rejection regions are x< 8.03 and x> 41.40eText(c) Find the standardized test statisticMultimedia Library(Round to two decimal places as needed.)Study PlanGet more help-Clear allCheck answerTools for SuccessHelp me solve thisView an exampleAccessible Resources9:4662*F ^@白a 会Skills for Success12/699+Type here to search3710/05/17InsertDelete口回F10PrtScF7F8F9F11F12FIF2F3F4F5F6&BackspaceNumLock+ ||%24

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Answered: A snack food manufacturer estimates…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A consumer group claims that the mean minimum time it takes for a sedan to travel a quarter mile is greater than 14.5 seconds. A random sample of 24 sedans has a mean minimum time to travel a quarter mile of 15.5 seconds and a standard deviation of 2.08 seconds. At α=0.05 is there enough evidence to support the consumer group's claim? Complete parts (a) through (d) below. Assume the population is normally distributed. (a) Identify the claim and state H0 and Ha. H0: Ha: (Type integers or decimals. Do not round.) The claim is the______hypothesis.
A random sample of 12 size AA batteries for toys yield a mean of 3.35 hours with standard deviation, 0.86 hours. Find the critical value, t*, for a 99% CI and the margin of error for a 99% CI.
A random sample of 8 size AA batteries for toys yield a mean of 3.41 hours with standard deviation, 1.3 hours. (a) Find the critical value, t*, for a 99% Cl. t* = (b) Find the margin of error for a 99% CI.
Before the furniture store began its ad campaign, it averaged 146 customers per day. The manager is investigating if the average is larger since the ad came out. The data for the 16 randomly selected days since the ad campaign began is shown below: 172, 147, 168, 163, 166, 139, 158, 151, 137, 140, 138, 137, 158, 133, 144, 144 Assuming that the distribution is normal, what can be concluded at the αα = 0.10 level of significance? H0: μ =146 H1 μ > 146 The test statistic t = 1.158 The p-value = 0.1325(Please show your answer to 4 decimal places.) The p-value is > αα Based on this, we should fail to reject accept reject the null hypothesis. (((((This is my question:)))) 3 questions sorry theres some reading Thus, the final conclusion is that ... The data suggest the populaton mean is significantly more than 146 at αα = 0.10, so there is sufficient evidence to conclude that the population mean number of customers since the ad campaign began is more than 146.…
Find the error margin for a 98% confidence interval for the average value of Y when X is 9.
A light bulb manufacturer guarantees that the mean life of a certain type of light bulb is at least 766 hours. A random sample of 30 light bulbs has a mean life of 754 hours. Assume the population is normally distributed and the population standard deviation is 61 hours. At α=0.08, do you have enough evidence to reject the manufacturer's claim? Complete parts (a) through (e). Identify the critical value(s). Use technology. Identify the standardized test statistic. Use technology. (d) Decide whether to reject or fail to reject the null hypothesis, and(e) interpret the decision in the context of the original claim.
An oceanographer claims that the mean dive duration of a North Atlantic right whale is 11.4 minutes. A random sample of 35 dive durations has a mean of 12.4 minutes and a standard deviation of 2.1 minutes. At α=0.10 is there enough evidence to reject the oceanographer's claim? Complete parts (a) through (d) below. Assume the population is normally distributed.
If the coefficient B₁ has a nonzero value, then it is helpful in predicting the value of the response variable. If ß₁ = 0, it is not helpful in predicting the value of the response variable and can be eliminated from the regression equation. To test the claim that B₁ = 0 use the test statistic t= (b₁-0)/sp. Critical values or P-values can be found using the t distribution with n - (k+ 1) degrees of freedom, where k is the number of predictor (x) variables and n is the number of observations in the sample. The standard error sp, is often provided by software. For example, see the accompanying technology display, which shows that sp, = 0.070227804 (found in the column with the heading of "Std. Err." and the row corresponding to the first predictor variable of height). Use the technology display to test the claim that B₁ = 0. Also test the claim that B₂ = 0. What do the results imply about the regression equation? Click the icon to view the technology output. Test the claim that B₁ = 0.…
Listed in the accompanying table are weights (kg) of randomly selected U.S. Army male personnel measured in 1988 (from "ANSUR I 1988") and different weights (kg) of randomly selected U.S. Army male personnel measured in 2012 (from "ANSUR II 2012"). Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b). Click the icon to view the ANSUR data. a. Use a 0.05 significance level to test the claim that the mean weight of the 1988 population is less than the mean weight of the 2012 population. What are the null and alternative hypotheses? Assume that population 1 consists of the 1988 weights and population 2 consists of the 2012 weights. OA. Ho: H1 H2 B. Ho: H1 H2 H₁: H1 H2 D. Ho: H₁₂ H₁₁₂ H₁: H₁₂ The test statistic is -2.60. (Round to two decimal places as needed.). The P-value is 0.008. (Round to three decimal places as needed.) State the…
WebAssign -→ xC OD Let x represent the number of mountain dimbers killed each year. The long term variance of x is approximately o= 136.2. Suppose that for the past 7 years, the vanance has been sE 110.6. Use a 1% level of significance to test the daim that the recent variance for number of mountain cimber deaths is less than 136.2., Find a 90% confidence interval for the population variance (a) What is the level of significance? State the null and alternate hypotheses. O Ho: a- 136.2; Hi o > 136.2 O Ho: - 136.2; Hạ o < 136.2 OHại o- 136.2; H o 136.2 O Hại a < 136.2; H o 136.2 (b) Find the value of the dhl-square statistic for the sample. (Round your answer to two decimal places.) What are the degrees of freedom? What assumptions are you making about the original distribution We assume a normal population distribution. We assume a binomial population distribution We assume a esponential population distribution We assume a uniform population distribution () Find or estimate the PyValue…
Listed in the accompanying table are weights (kg) of randomly selected U.S. Army male personnel measured in 1988 (from "ANSUR I 1988") and different weights (kg) of randomly selected U.S. Army male personnel measured in 2012 (from "ANSUR II 2012"). Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b). Click the icon to view the ANSUR data. a. Use a 0.05 significance level to test the claim that the mean weight of the 1988 population is less than the mean weight of the 2012 population. What are the null and alternative hypotheses? Assume that population 1 consists of the 1988 weights and population 2 consists of the 2012 weights. A. Ho: H1 H2 H₁₁ H₂ C. Ho H₁ =H2 H₁: H1 H2 OB. Ho: H1 H2 H₁₁₂ OD. Ho: H1 H2 ANSUR data The test statistic is . (Round to two decimal places as needed.) ANSUR II 2012 ANSUR I 1988 80.9 85.6 83.5 73.9 103.7 78.6…
what do part b and part f say? I'm unsure what all the words say.

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