**Question:**c. Compute the value of the test statistic. *(Round your answer to 3 decimal places.)***Answer:**- **Value of the test statistic:** [Input box here, visual cue of a blue label reading "Value of the test statistic"] ### Hypothesis Testing: Comparing Population Means**Null and Alternate Hypotheses:**- Null Hypothesis (H₀): μ₁ = μ₂- Alternate Hypothesis (H₁): μ₁ ≠ μ₂**Sample Data:**- **First Population:** - Sample Size (n₁): 15 - Sample Mean (x̄₁): 350 - Sample Standard Deviation (s₁): 12- **Second Population:** - Sample Size (n₂): 17 - Sample Mean (x̄₂): 342 - Sample Standard Deviation (s₂): 15Assumptions:- Population variances are assumed to be equal.**Significance Level:**- α = 0.10**Research Question:**- At the 0.10 significance level, is there a difference in the population means?**Analysis:****a. Type of Test:**- Is this a one-tailed or a two-tailed test? - ☑ Two-tailed test**b. Decision Rule:**- Negative amounts should be indicated by a minus sign. Round your answers to three decimal places.- The decision rule is to reject H₀ if t < [ ] or t > [ ] Fill in these values depending on the calculated critical values for the t-distribution at the specified significance level.

Answered: The null and alternate hypotheses are:…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are interested in testing whether the average age of household heads is higher in the suburbs than in inner city neighbourhoods. A survey is conducted, and the following results are obtained. In the suburbs, the household heads of the 45 households surveyed had a mean age of 44 with a standard deviation of 15. In the inner city, the mean age of the 40 household heads surveyed was 38 with a standard deviation of 13. Assuming that the populations from which these samples were drawn have equal variances, can you conclude that the difference between the two means is significant at the 95% level of confidence? (a) Write in words and symbols the null and research hypotheses. (b) Assuming the variances of the populations are equal, calculate the value of the Pooled Variance Estimate (PVE). (c) Calculate the value of the standard error for the difference between the two means.
The average American consumes 89 liters of alcohol per year. Does the average college student consume less alcohol per year? A researcher surveyed 15 randomly selected college students and found that they averaged 87.3 liters of alcohol consumed per year with a standard deviation of 15 liters. What can be concluded at the the a = 0.05 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Но: ? Select an answer V Н: ? v Select an answer V c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? v a f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... the null hypothesis. O The data suggest the population mean is not significantly less than 89 at a = 0.05, so there is statistically insignificant evidence to conclude that the population mean amount of alcohol consumed by college students…
The next six questions refer to the following scenario: A random sample of 25 students were asked to self-identify as "statistics-lovers" or "statistics-adorers." 16 students self-identified as "lovers" and 9 students as "adorers." Below table summarizes the mean of a statistics test and standard deviation that was given after the self-identification. Test the following hypothesis at alpha=5% (0.05). HO: Mean Statistics Lovers = Mean Statistics Adorers HA: Mean Statistics Lovers Mean Statistics Adorers You can assume equal variance.
Step 1 of 3. State the null and alternative hypotheses for the test. Step 2 of 3. Compute the value of the test statistic. Round your answer to three decimal places Step 3 of 3. Draw a conclusion and interpret the decision.
The average dues paid by students at state universities across the country were $2236 per student last year. The average for a random sample of 500 students this year is $2350. Given the following hypotheses, Ho: 4 = 2236 (The average fees are the same as last year.) Ha: M + 2236 (The average fees are not the same as last year.) compute the p-value for the sample result. Assume the population standard deviation is $724. If the significance level is 5%, can the null hypothesis be rejected?
Read each situation and perform the appropriate test of hypothesis for the one sample mean z-test and t-test. 2. A manufacturer claims that their car batteries have a mean life expectancy of 6 years with a population standard deviation of 1.75 years. In order to test its own claim, a random sample of 35 batteries were tested and it was found out their mean life span is 5. 5 years. Is there evidence at the 0.01 level of significance that the batteries become exhausted in less than 6 years?
If the t-statistic for a single sample t-test is 1.58, what can you conclude? a. The test is significant at an alpha level of .05. b. The sample size of the test was at least 30. c. The sample mean was larger than the population mean. d. The population standard deviation was smaller than the difference between the sample mean and the population mean.
Medicare would like to test the hypothesis that the average monthly rate for one-bedroom assisted-living facility is equal to $3,300. A random sample of 12 assisted-living facilities had an average rate of $3,690 per month. The standard deviation for this sample was $530. Medicare would like to set α = 0.02. The critical value for this hypothesis test would be
A Moving to another question will save this response. Question 1 Consider a sample with a mean of 30 and a standard deviation of 2.5. Use Chebyshev's theorem to determine the percentage of the data within the ranges from 23 to 37. O a. 61% O b. 75% O c. 87% Od. 83%
1. In a random sample of fishes from a pond, the mean tail length was 6.0 mm and the reference tail length for the species was found to be 4.0 mm with a standard deviation of 2.0. if there are 16 fishes, what would be the z score and which hypothesis would be accepted? 2. If the mean for group 1 in a clinical trial for the time for a drug X to act is 10 minutes and 8 minutes for group 2 and if the standard deviation for group 1 is 1.0 and group 2 is 2.0. If there are 4 persons in both groups, what is the t value and which hypothesis would you accept if t critical is 3.14 ( 2 sided) 3. A geneticist is examining the relationship between genotype and phenotype for roses. He calculated a chi-square value of 4.1 for a 2 x 2 table. If the scenario is two sided, which hypothesis did he accept? 4.
Question 20. part b. Nationally, patients who go to the emergency room wait an average of 7 hours to be admitted into the hospital. Do patients at rural hospitals have a lower waiting time? The 14 randomly selected patients who went to the emergency room at rural hospitals waited an average of 5.8 hours to be admitted into the hospital. The standard deviation for these 14 patients was 1.7 hours. What can be concluded at the the αα = 0.05 level of significance level of significance? C.)The test statistic ?, z or t = ____ (please show your answer to 3 decimal places.) D.)The p-value = ______ (Please show your answer to 4 decimal places.) E.) The p-value is ?, ≤ , > α

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