A professor suspects that the more often students attend their online lecture the better they will do on their quiz. Which of the following would be the null hypothesis for this professor's study?
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- Part 1 of 4 A pharmaceutical company claims their new diabetes medication results in less variance in a patient's glucose level than if the patient were on no medication at all. An endocrinologist wishes to test this claim. She divides participants randomly into two groups. Group A consists of 20 diabetics who received the medication; group B consists of 26 diabetics who received a placebo. After two weeks, the blood sugar level of each patient in each group was measured with the following results (in mg/dL): Group A: 77.8, 229.4, 199.9, 110.1, 180.2, 116.1, 139.7, 171.1, 37.4, 158.1, 88.4, 195.5, 246.1, 142.4, 178.1, 105.5, 179.6, 146.1, 78.8, 123.7 Group B: 124.5, 130.1, 136, 162.8, 113.4, 72.8, 142.6, 50.3, 179.8, 197, 230, 194.3, 171, 109.3, 114.4, 107.5, 114.7, 195.3, 127.7, 126.4, 85.6, 166.7, 182.3, 113.5, 216.7, 162.8 Perform a hypothesis test using a 6% level of significance to test the pharmaceutical company's claim. Step 1: State the null and alternative hypotheses. Ho: Ha:…In Chapter 17 Data Set 5, you will find entries for two variables: age category (young, middle-aged, and old) and strength following weight training (weak, moderate, and strong). Are these two factors independent of one another? Strength Weak Moderate Strong Age Young 12 18 22 Middle 20 22 20 Old 9 10 5 What is the null hypothesis in words? (You will need to get this from lecture and/or the lecture notes. It is not covered in your text). What is the alternative hypothesis in words? (See note in a. above) What is your degrees of freedom for the test? How did you arrive at this answer? Based on c. above and using an alpha =.05, what is the critical value for the test? Use PSPP/SPSS to calculate the Chi Square value. Use the instructions on pages 304-305. Copy/paste the output table. (result in the pictures) What is the Chi Square value? What is the p-value? Based on f., do…Answer true or false to each of the following statements and explain your answers. a. In a two-way ANOVA, if there is an interaction between Factor A and Factor B, then there must be a main effect due to at least one of the factors.b. In a two-way ANOVA, if there is no Factor A main effect and no Factor B main effect, then there can be no interaction effect between Factor A and Factor B.
- Which of these is a manifestation of null hypothesis? a. As temperature increases so too will the level of aggression b. Older adults will have worse memories than younger adults c. There will be no relationship between caffeine consumption and performance d. There will be a significant difference between group 1 and group 2A poll reports that 47% of Canadians download movies on their computers.The poll has a margin of error of 4.8%, 19 times out of 20.Choose the statement that best explains what this means. Question 6 options: If you had taken another poll, there is a 95% chance that somewhere between 51.8% and 42.2% of people polled would download movies. If you had taken another poll, there is a 90% chance that somewhere between 51.8% and 42.2% of people polled would download movies. If you had taken another poll, there is a 19% chance that somewhere between 49.4% and 44.6% of people polled would download movies. If you had taken another poll, there is a 95% chance that somewhere between 49.4% and 44.6% of people polled would download movies.Annie conducts a study to examine the differences in stress levels between pet owners and non-pet owners. She conducts a two-tailed test and tells that she rejected the null hypothesis. Therefore, which of these statements is true? Question 8 options: Pet owners have more stress than non-pet owners. Pet owners have less stress than non-pet owners. Pet owners' and non-pet owners' stress levels differ, but it is not known how they differ. Pet owners' and non-pet owners' stress levels do not differ.
- Brett is a huge sports fan. He hypothesized half of sports fans liked football the best, 25% liked baseball the best, 15% liked basketball the best, and 5% liked hockey the best, and the rest liked some other sport the best. He surveyed 500 sports fans and asked what sport they liked the best. Which of the following is the way to calculate the number of these 500 sports fans expected to say that basketball is their favorite sport if the null hypothesis is true? ...... Choose the correct answer below. A. (500)(0.20) B. 500 - (500)(0.20) 500 C. 0.15 D. (500)(0.15)need help please!??
- QUESTION 2 You conduct a study to understand whether happy people are more likely to exercise than sad people. In your sample of happy people. 25 chose to exercise and 10 chose to take a nap. In your sample of sad people, 5 chose to exercise and 35 chose to take a nap. (1) What is the null hypothesis? a. There is a difference in rates of exercise among happy and sad people. b. There is an association in rates of exercise among happy and sad people. c. There is not a difference in rates of exercise among happy and sad people. d. There is not an association in rates of happiness among those who exercise and those who nap. (2) What is the expected frequency for happy people who exercise? (3) What is the expected frequency for sad people who exercise? (4) What is the expected frequency for happy people who nap? (5) What is the expected frequency for sad people who nap? (6) What is your chi-square value? (7) How many degrees of freedom are there? (8) Assuming alpha is equal to .05, what is…You are testing the difference between high school freshmen and seniors on SAT performance. The null hypothesis is that the population mean SAT score of the seniors is equal to the population mean SAT score of the freshmen. You randomly sample 20 students in each grade and have them take the SAT. You find that the sample mean of the seniors is significantly higher than the sample mean of the freshmen. Which alternative hypothesis is accepted? The population mean SAT score of the seniors is less than the population mean SAT score of the freshmen. The population mean SAT score of the seniors is greater than the population mean SAT score of the freshmen. You cannot be sure which alternative hypothesis to accept. You just know that the null hypothesis was rejectedMr Alsup asked the studentS in his third-and sixth-period English classes whether they had chosen a topic for thier writing assignment. he recorded the data in a two-way table, as shown below English class Yes No Total Third period 24 6 30 Sixth period 22 3 25 Total 46 9 55 if jannette in in mr alsup sixth-period english class what is the probablity that she has not chosen a topic for her writing assignment? a- 3% b- 5% c- 12% d-14%
