A pollutant is being removed in a batch reactor by a 2nd order reaction. 1) Write the rate equation for the 2nd order reaction in the batch reactor. 2) Determine the pollutant concentration at the end of the reaction, which is 10 hours from the beginning of the reaction. It is known that the initial concentration is 300mg/L and the concentration reduces to 100mg/L after 5 hours. (1/C = 1/C_o + kt).
A pollutant is being removed in a batch reactor by a 2nd order reaction. 1) Write the rate equation for the 2nd order reaction in the batch reactor. 2) Determine the pollutant concentration at the end of the reaction, which is 10 hours from the beginning of the reaction. It is known that the initial concentration is 300mg/L and the concentration reduces to 100mg/L after 5 hours. (1/C = 1/C_o + kt).
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A pollutant is being removed in a batch reactor by a 2nd order reaction. 1) Write the rate
equation for the 2nd order reaction in the batch reactor. 2) Determine the pollutant concentration at the
end of the reaction, which is 10 hours from the beginning of the reaction. It is known that the initial
concentration is 300mg/L and the concentration reduces to 100mg/L after 5 hours. (1/C = 1/C_o + kt).
Expert Solution
Step 1
Given data
2nd order reaction
initial concentration is 300mg/L
concentration reduces to 100mg/L at times t= 5hr
Final time t= 10 hr
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